The topic is probably given to a main string, asking for several occurrences of a pattern string, some of which require no overlap.
For overlapping is a straightforward multi-pattern matching problem, but not overlapping, in the matching process greedy record the current matching of the main string position, and then whenever a new match according to the location of the record to determine whether the new match is established, the last update location.
In addition, given that the data can occur in multiple pattern strings the same situation, the implementation to do some processing:
1#include <cstdio>2#include <cstring>3#include <queue>4#include <algorithm>5 using namespacestd;6 #defineMAXN 6666667 //-1 None, 0 overlap, 1 not, 2 all8 inttn,ch[maxn][ -],FAIL[MAXN],FLAG[MAXN],LEN[MAXN];9 intInsertChar*s,intk) {Ten intx=0, l=0; One for(intI=0; T[n]; ++i) { A inty=s[i]-'a'; - if(ch[x][y]==0) ch[x][y]=++tn; -x=Ch[x][y]; the++l; - } -len[x]=l; - if(flag[x]==-1) flag[x]=K; + Else if(flag[x]==0&& k==1) flag[x]=2; - Else if(flag[x]==1&& k==0) flag[x]=2; + returnx; A } at voidGetfail () { -memset (fail,0,sizeof(flag)); -queue<int>que; - for(intI=0; i< -; ++i) { - if(ch[0][i]) Que.push (ch[0][i]); - } in while(!Que.empty ()) { - intx=Que.front (); Que.pop (); to for(intI=0; i< -; ++i) { + if(Ch[x][i]) { - Que.push (Ch[x][i]); thefail[ch[x][i]]=Ch[fail[x]][i]; *}Elsech[x][i]=Ch[fail[x]][i]; $ }Panax Notoginseng } - } the intlast[maxn],ans[2][maxn],first[111111],second[111111]; + Charstr[111111]; A voidquery () { the intx=0; + for(intI=0; Str[i]; ++i) { - inty=str[i]-'a'; $ inttmp=x=Ch[x][y]; $ while(TMP) { - if(flag[tmp]!=-1&& flag[tmp]!=1) ++ans[0][tmp]; - if(flag[tmp]!=-1&& flag[tmp]!=0){ the if(last[tmp]==-1|| i-last[tmp]>=Len[tmp]) { -last[tmp]=i;Wuyi++ans[1][tmp]; the } - } Wutmp=fail[tmp]; - } About } $ } - intMain () { - intN,cse=0; - Chars[ One]; A while(~SCANF ("%s", str)) { +tn=0; thememset (CH,0,sizeof(CH)); -memset (flag,-1,sizeof(flag)); $scanf"%d",&n); the for(intI=0; i<n; ++i) { thescanf"%d%s",&first[i],s); thesecond[i]=Insert (S,first[i]); the } - Getfail (); inmemset (ans,0,sizeof(ans)); thememset (last,-1,sizeof(last)); the query (); Aboutprintf"Case %d\n",++CSE); the for(intI=0; i<n; ++i) { theprintf"%d\n", Ans[first[i]][second[i]]); the } +Putchar ('\ n'); - } the return 0;Bayi}
ZOJ3228 searching the String (AC automaton)