amd 4870

HDU 4870 Rating Gaussian elimination method, hdu4870 Link: http://acm.hdu.edu.cn/showproblem.php? Pid = 1, 4870 Assume that you use two accounts to participate in a competition. In the initial state, both accounts have zero points. Each game uses a low-score account to compete. A probability of winning a game is P, the score of the corresponding account increases by 50 points. Otherwise, the score of the co

HDU 4870 Rating (Gaussian deyuan), hdu4870HDU 4870 Rating Question Link A person registers two accounts, and the initial rating is 0. He plays the game with the low score each time. After winning the game, he adds 50 points and deducts 100 points. The winning rate is p, he will hit the game until he scored 1000 points on the first day and asked about the expectations of the game. Train of Thought: f (I, j)

Http://acm.hdu.edu.cn/showproblem.php? PID = 1, 4870 Question: There are two numbers, and the initial score is 0. Each time you choose a game with a small score, if you choose one with the same score, the probability of a P score increases by 50 points, and the maximum score is 1000 points, A probability of 1-P drops by 100,The minimum value is 0.. I would like to ask you the expected number of times you want to play the game when the number reaches

number p (0.3 OutputYou should output a float number for each test case, indicating the expected count of contest she needs to participate in. This problem is special judged. The relative error less than 1e-5 would be accepted.Sample Input1.000000 0.814700Sample Output39.000000 82.1811601#include 2#include string.h>3#include 4 using namespacestd;5 6 intMain ()7 {8 inti,j;9 Doubledp[ A],p,ans[ -][ -];Ten while(SCANF ("%LF", p)! =EOF) One { Adp[0]=1.0/p; -dp[1]=1.0/p/p; -ans[0][0

In fact, zoj 3415 should be called Yu Zhou... After encountering zoj 3415, I used the second method of Reference URL to seek the communication item, and this time I met 4870, I won't do it. After referring to chanme, I re-deduced zhou Yu and the ranking repeatedly (not to push down) four or five times to write this question about plagiarism... These two questions are very similar. Multi-school rating is equivalent to a forced version, but the principl

HDU 4870 Rating (Gaussian deyuan)HDU 4870 Rating Question Link A person registers two accounts, and the initial rating is 0. He plays the game with the low score each time. After winning the game, he adds 50 points and deducts 100 points. The winning rate is p, he will hit the game until he scored 1000 points on the first day and asked about the expectations of the game. Train of Thought: f (I, j) indicates

, probability is P, expectation is 1*p2. Failure. Probability 1-p. Expected for (1-p) * (1+dp[0])-----so dp[0]=1*p+ (1-p) * (1+dp[0]), dp[0]=1/p after simplification;DP[1] Represents the number of fields we expect from 50-100, divided into two cases: 1. Success, probability is P, expectation is 1*p2. Failure, probability 1-p, expectation (1-p) * (1+dp[0]+dp[1])-----so dp[1]=1*p+ (1-p) * (1+dp[0]+dp[1]), dp[1]=1+ (1-p)/p* (1+dp[0]) after simplification;I>2,dp[i] is divided into two cases: 1. Succ

Links: http://acm.hdu.edu.cn/showproblem.php?pid=4870Test instructions: With two accounts to participate in a game, the initial state of two accounts are 0 points, each game with a low score of the account to play. have p probability to win, the corresponding account score up 50 points, or the corresponding account score down 100 points, ask when there is an account score of 1000 time to participate in the number of mathematical expectations of the game.Idea: During the game thought is a formula

Link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 4870 Assume that you use two accounts to participate in a competition. In the initial state, both accounts have zero points. Each game uses a low-score account to compete. A probability of winning a game is P, the score of the corresponding account increases by 50 points. Otherwise, the score of the corresponding account decreases by 100 points. Ask the expected number of times of participation in

[HDU 4870] Rating [DP], hdu4870rating A person registers two accounts, and the initial rating is 0. He plays the game with the low score each time. After winning the game, he adds 50 points and deducts 100 points. The winning rate is p, he will hit the game until he scored 1000 points on the first day and asked about the expectations of the game. Question: because each time we increase or decrease the score is a multiple of 50, we can compress it into

Original: http://villadora.me/2014/05/23/amd-define-and-how-to-translate-amd-to-commonjs/There has been a lot of controversy between Commonjs and AMD, and both have evolved and converged on the project. Personally, Commonjs is more developer-oriented, and for developers, it requires a clear version and management, less code and more interference, and less configu

Asynchronous modules define AMD and asynchronous modules amd It is called Asynchronous Module Definition, and is defined by Asynchronous components (or modules. AMD is a mechanism in which components and their dependencies can be asynchronously loaded.Define Method define(id?, dependencies?, factory); Component ID The component ID is the unique identifier of a c

Although AMD's day-to-day task is to zen the momentum, but after all Zen the fastest also have to be the end of the year or the beginning of the IPO. In such a gap, the addition of the upgrade is the pain before the dawn. As a representative of AMD High-performance CPU--FX series, although its historical evaluation has long been conclude, but the market always has a place for the FX series. This year, AMD s

Earlier graphics cards were only used for display, and then 2D acceleration components were added to the graphics card, which were used for the operation of the screen, draw points, draw lines, and so on. With the need of game, three-dimensional simulation and scientific computing visualization, the demand for 3D is gradually increasing, the early drawing work is done by the CPU, to achieve realism and real-time effect, can only draw some simple wireframe model, in the 80 's, Stanford University

queue.The 2703 line involves the fence mechanism, which we'll cover in detail in the interrupt mechanism section.The same code that reads the indirect buffer mechanism is not too difficult.Indirect buffer to be able to function properly, it must be inserted into the code of the ring buffer, which is similar to inserting a "call xx" directive into the assembly code for function calls. The command added by the Radeon_ring_ib_execute function is equivalent to the call instruction used when the fun

This one test is the flagship model of the next generation of "Bristoal Ridge" processors: a12-9800. Compared to the previous generation of APU, this generation of AMD CPUs supports ddr4-2400 memory, NMVE protocol SSD, providing greater bandwidth and support for USB 3.1. From the extended functionality to catch up with Intel's mainstream processor. Let's take a look at the CPU performance of the a12-9800. Judging

The previous blogs have described some of the DRM drivers, graphics card memory management mechanisms, and interrupt mechanisms, and it should be much easier to read the AMD DRM-driven initialization process.Here is an article written by an AMD developer (put it here for the time being, and then add your own view later).Understanding GPUs from the ground upI get asked a lot on learning how to program GPUs.

scratch register will tell you which interrupt was generated by the drawing command.The fence interrupt handler function is radeon_fence_poll_locked. First read the fence number, know that the fence operation caused the interruption, when the resulting interrupt fence number is the last number, you need to assign the last fence number to the current number, while updating the fence timer. If the interrupt is not the last fence number, the timer needs to be judged and then the fence interrupt qu

(ret) {fprintf (stderr, "failed to retreive buffer stride:%s\n", Strerror (-ret));Kms_bo_destroy (BO);return NULL;21}ret = Kms_bo_map (bo, virtual);if (ret) {fprintf (stderr, "failed to map buffer:%s\n", Strerror (-ret));Kms_bo_destroy (BO);+ Return NULL;27}return Bo;This code is similar to the code in the kernel, and the reader should be able to understand its meaning based on the function name of the called function. To write a complete program, you can refer to the LIBDRM source code or the

Knowledge Point Analysis: Common "double A platform" models are:G485, Y485, S415, S405, S435, Bxx-45, Gxx-45, Nxx-45 and other models Test Platform:S415 Touch, Cpu:amd a4-5000m (HD 8330); GPU:AMD Radeon 8570M Operation steps: 1, right click on the desktop, select "Configure interchangeable display card"; 2, open AMD CCC, click on "All Applications", where you can individually switch control of a single process video card settings; 3