Talking about automatic summarization algorithm, common and most easily realized when belong to TF-IDF, but feel tf-idf effect general, inferior to textrank good. Textrank is inspired by Google's PageRank algorithm, which aims at automatic summarization of the weighted algorithm for sentence design in text. It uses the principle of voting, so that each word to its neighbors (the term window) vote in favour of the vote, the weight of the vote depends on the number of votes. This is a "first chick
implements an interfaceImport//Importing Classinstanceof//test whether an object is an instance of a classint//32-bit integer numberinterface//interface, an abstract type, only the definition of methods and constantsLong//64-bit integer numberNative//representation method implemented in non-Java codeNew//Allocation of class instancesPackage//series of related classes make up a bundlePrivate//Represents a proprietary field, or method, etc., accessible
:" +he.num1); +System.out.println ("num2:" +he.num2); ASystem.out.println ("num3:" +num3); atHello he1 =NewHello (); - } -}What about this output? The output may be the opposite of what we imagined, the correct output is as follows:Assigning values to num3 by static initialization blocksAssigning values to num2 by initializing blocksAssigning a value to a num1 by constructing a methodNum1:30Num2:60Num3:90Assigning values to num2 by initializing blocksAssigning a value to a num1 by constructi
Generally, it is seldom formatted or parse strings with English words such as Sun Nov.
If you format the string of the English month, remember to include the locale. Us parameter. Otherwise, the JRE will be interpreted according to the language format of the current region, and an error will occur.
string a = "Sun Nov 13 21:56:41 + 0800 2011"; simpledateformat SDF = New simpledateformat (" eee Mmm dd hh: mm: ss z yyyy ", locale. US); ///
Question: Count the number of occurrences of a word in a storyIdeas:(1) The article (a string store) is stored in a string (word) array after splitting (split) by a space.(2) Define a map,key is a string type, save the word; value is a numeric type that holds the number of occurrences of the word.(3) traversing (1) The resulting string array, for each word, the study of the map key in the occurrence of the word, if not, add an element in map, key is the word, value is 1 (first occurrence);If the
Given an input string, reverse the string word by word. For Example,given s = "The Sky is Blue" and return "Blue is Sky the". Update (2015-02-12): For C programmers:try to solve it in-place in O (1) space.Test instructions: Reverse the word in the string, pay attention to the processing of the space!!!Publicclasssolution{publicstringreversewords (String s) {intlength=s.length (); //char[]ch=s.tochararray (); if (s==null| | length==0) returns;intend=length; stringbuilderret=newstringbuilder (); f
Given an input string, reverse the string word by word.For example,Given s = " the sky is blue ",Return " blue is sky the ".Click to show Clarification.Clarification:
what constitutes a word? A sequence of non-space characters constitutes a word.
could the input string contain leading or trailing spaces? yes. However, your reversed string should not contain leading or trailing spaces.
how about multiple spaces between? reduce them to a single space in the reversed string.
there is no sensitive words (I am also afraid of being shielded XD), the test when casually add a few sensitive words can be detected. This enables a simple and fast detection of sensitive words, of course, if there is a need for more sophisticated detection logic (such as "guitar mother is really beautiful"), or to use the word breaker tool to split the
, finalFinal is not commonly used in Java, but it gives us the ability to define constants in the C language, and final allows you to control your members, methods, or whether a class is capable of overwriting or inheriting, These features make final an integral part of Java and one of the key words that you must know and master when learning java.Final memberWhe
Problem:You is given a string, s, and a list of words, words, that is all of the same length. Find all starting indices of substring (s) in s that's a concatenation of each word in wordsexactly once And without any intervening characters.for example, given:s : " Barfoothefoobarman " words : [" foo "," Bar "] You should return the indices: [0,9] .(Order does not
some cases to simplify the code. However, code that uses volatile is often more error-prone than code that uses locks. the patterns described in this article cover some of the most common use cases where you can use volatile instead of synchronized. Following these patterns (note that you do not exceed their limits when you use them) can help you achieve most of the use cases securely, using volatile variables for better performance.
Three: Java sync
...... Suddenly found that the String.IndexOf method cannot return all index, only the first and last, um ... Purely manual traversal of a wave? Give it a try.Try to write the discovery to use ArrayList, because directly with int[] can not determine the length, the efficiency is certainly reduced.So in the future, the problem of split indeterminate length is to use split bar, with a fixed length and a limited number of split can try a faster original method.In addition to see discuss area This a
the operand stack and return to the calling methodIload_2//Push local varaible 2-the 100Ireturn//return int on top of the stack-the 100:return 100Because the return statement saves the returned value to a temporary local variable before it returns, the value is re-assigned within the FINALLY clause without affecting the return value.Understanding some of the inner knowledge of the finally clause allows us to understand what finally can and cannot do, which will help us to use the finally clause
{PublicStaticvoidMain(String[]Args){AnimalAm=NewCat();am...//system.out.println (Am.name),//Here first note, will explain .. (am. Numsystem.. (am. Age} /span> The above three-segment code fully embodies the polymorphism of the three prerequisites, namely: 1, there is an inheritance relationship Cat class inherits the Animal Class 2, subclasses to override the parent class's method Subclass overrides (override) The parent class two member Method Eat (), sleep ()。 w
I. Description of the topicGiven an input string, reverse the string word by word.For example,Given s = " the sky is blue ",Return " blue is sky the ".Second, analysisNote the following: 1. When there are spaces in the head or tail of a string, the end is eliminated2, when the number of spaces between two substrings is greater than 1 o'clock, just keep aProblem-Solving ideas: 1, first, the entire string is reversed2. Then, use the Split function to cut the string and get each string reversed3. F
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