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SQL statement for average score of Student Course Selection

There is a student table with three columns in total. The first column is the student ID column, which stores the student ID of the Course Selection. You can repeat it to allow one student to select multiple courses. The second column is the course column, that is, the name of the course selected. The third column is the score column, that is, the score of the student. The student table contains the foll

13. Calculate the average score

Packagecn.jbit.loops2;ImportJava.util.*; Public classaveragescore{/*** Statistics of 80 and above student ratio*/ Public Static voidMain (string[] args) {intScore;//the results of each course intsum = 0;//The sum of achievements Doubleavg = 0.0;//Average scoreScanner input =NewScanner (system.in); System.out.print ("Enter Student's name:"); String name=Input.next (); for(inti = 0; I //Cycle 5 Entry 5 Course resultsSystem.out.print

awk application-Calculate student's average score

Let's look at an example of an awk application that adds a series of students ' scores and then calculates their averages. Here is the specific data for the input file:$CatGradesJohn - the +94 theAndrea the - the - theJasper - the the the -There are 5 grades behind the student's name. The following script will give the average score for each student:$CatGrades.awk#求5个成绩的平均值{Total= $+ $+$4 + $+$6Avg=Tota

HDU 2023 average score

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 2023 Question: calculate the average score of each student and the average score of each course, and output the score of each subject is greater than or equal to the average

PHP keyboard input Four student number name Chinese mathematics English information, calculate the average score of each student, output

-Keyboard input Four student number name Chinese mathematics English information, calculate the average score of each student, output -The student's information includes the school number name Chinese mathematics English average score, 4 student's information in the array. $student=Array();$student=Array(Array(' name

Zoj 3819 average score (mathematical problem Mudanjiang)

Zju math zoj Mudanjiang Question link: http://acm.zju.edu.cn/onlinejudge/showProblem.do? Problemid = 5373 Bob is a freshman in marjar University. He is clever and diligent. However, he is not good at math, especially in mathematical analysis. After a mid-term exam, Bob was anxious about his grade. He went to the specified sor asking about the result of the exam. The specified sor said: "Too bad! You made me so disappointed ." "Hummm... I am giving lessons to two classes. If you were in the

Enter the number of people, input fractions, save in the collection, and then read out, to find the average score

Console.Write ("Please enter the number of classes:"); intn =Convert.ToInt32 (Console.ReadLine ()); ArrayList Fenshu=NewArrayList (); Doublesum =0; for(inti =0; I //to enter the elements of a collection with a For loop{Console.Write ("Please enter section"+ (i+1)+"Personal Score:"); Fenshu. ADD (Double. Parse (Console.ReadLine ()));//cast receive data type is double typeSum + =Double. Parse (Fenshu[i]. ToString ());//casts a collection element to a s

Judges scoring problem---remove two highest points, two minimum points, to find the average score

//judges scored minus two highest points minus two minimum points for averaging int[]defen={78,79,80,83,89,99,90,76,88,98}; for(inta=0;a) {System.out.print (Defen[a]+ "\ T"); } System.out.println ();//The first step, initialize for(intb=1;b) { for(inta=0;a) { if(defen[a]>defen[a+1]) { intt=Defen[a]; Defen[a]=defen[a+1]; Defen[a+1]=T; }} for(inta=0;a) {System.out.print (Defen[a]+ "\ T");} System.out.printl

1148:0 start-up algorithm 55--print all points below the average score

1148:0 start-up algorithm 55--print all points below average time limit:1 Sec Memory limit:64 MB 64bit IO Format:%lldsubmitted:2456 accepted:777[Submit] [Status] [Web Board] DescriptionEnter n scores to print out all points below the average score (Note: Ave = S/n is float or ave = (float) n/a).InputMultiple test dataEach test data row, in this line firs

Array name as function parameter (average student score)

In addition to using array elements as function parameters, you can also use the array name as a function parameter (including arguments and formal parameters) should be noted that the array element as an argument is passed the value of the array element, and the array name as the function argument, the parameter (function name or pointer variable) is passed the value of the first address of the array.#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permi

Using ArrayList to enter students ' grades, the average score and total scores are calculated.

Console.WriteLine ("Please enter the number of students:"); intn=int. Parse (Console.ReadLine ()); ArrayList arr=NewArrayList (); for(inti =0; I ) {Console.WriteLine ("The result of the entry of the {0} individual is:", i+1); Arr. ADD (int. Parse (Console.ReadLine ())); } foreach(intAincharr) {Console.Write (a+"\ t"); } Console.WriteLine (); Doublesum =0;intMax =0; for(intj =0; J ) { if(int. Parse (Arr

Average score (hdu2023)

Note: To cautious, do not mistake in small details. such as int c[6];d ouble Agve; C[j]=agve; this is wrong.#include #includeinta[Wuyi][6];Doublec[6];intMain () {intN; intm; CharD; while(scanf_s ("%d%d%c", n, m, d)! =EOF) { for(inti =0; i) { for(intj =0; j) { intb; scanf_s ("%d", b); A[I][J]=b; } } for(inti =0; i) { Doublesum =0; DoubleAvge; for(intj =0; j) {sum= Sum +A[i][j]; } Avge= sum*1.0/m; printf ("%0.2

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