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;l.sort (reverse=true) >>>l>>>[4,3,2,1] Example 3: Sort the second keyword >>>l = [(' B ', 6), (' A ', 1), (' C ', 3), (' d ', 4)]>>>l.sort (Lambda x,y:cmp (x[1],y[1])) >>>L> >>[(' A ', 1), (' C ', 3), (' d ', 4), (' B ', 6)] Example 4: Sort the second keyword >>>l = [(' B ', 6), (' A ', 1), (' C ', 3), (' d ', 4)]>>>l.sort (Key=lambda x:x[1]) >>>l>>>[( ' A ', 1), (' C ', 3), (' d ', 4), (' B ', 6)] Example 5: Sort the second keyword >>>l = [(' B ', 2), (' A ', 1), (' C ', 3), (' d ', 4)]>
LAN), QQ softwareVI, network switching technology:Multiplexing: FDMA, WDMA, TDMA, CDMA frequency-wave time Code Division multiplexingNetwork switching technology: circuit switching, storage and forwarding (message exchange), datagram, virtual circuit, ATMSeven, network storage technology:DAS, NAS, SANRAID Redundancy TechnologyEight, network access technologyADSL, HFC (fiber and coaxial cable hybrid network), high-speed Ethernet, DDN access (using digital channel transmission, equipment includin
;>>[4,3,2,1] Instance 3: sort the second keyword >>>L = [('b',6),('a',1),('c',3),('d',4)]>>>L.sort(lambda x,y:cmp(x[1],y[1])) >>>L>>>[('a', 1), ('c', 3), ('d', 4), ('b', 6)] Example 4: sort the second keyword >>>L = [('b',6),('a',1),('c',3),('d',4)]>>>L.sort(key=lambda x:x[1]) >>>L>>>[('a', 1), ('c', 3), ('d', 4), ('b', 6)] Instance 5: sort the second keyword >>>L = [('b',2),('a',1),('c',3),('d',4)]>>>import operator>>>L.sort(key=operator.itemgetter(1)) >>>L>>>[('a', 1), ('b', 2), ('c',
() does not return an object, changing the original list.Other examples of sort:Example 1: Forward Ordering >>>l = [2,3,1,4] >>>l.sort () >>>l >>>[1,2,3,4] Example 2: Reverse sorting >>>l = [2,3,1,4] >>>l.sort (reverse=true) >>>l >>>[4,3,2,1] Example 3: Sort the second keyword >>>l = [(' B ', 6), (' A ', 1), (' C ', 3), (' d ', 4)] >>>l.sort (Lambda x,y:cmp (x[1],y[1])) >> >l >>>[(' A ', 1), (' C ', 3), (' d ', 4), (' B ', 6)] Example 4: Sort the second keyword >>>l = [(' B ', 6), ('
The following characters are the decrypted strings in irisskin2.If you are interested, you can study it.Put the text in notepad, delete "enter", and put it in a line Dceqrmao1kvrmgl/fwhjgrnqug4ou/cisgw1 + DSU/iihskbzV4q ==Wt + C/hfeidcpzilyuomxd1thv3n1uiba35ddrzqz25o9pmmtaehiBzagpik5/qhdgf + sgm76qags5pzmm3da ==Khfnvp000ikyln91yvkvb3qek3zcfafernwgpyek6d05pzulawriWooeal69t/wpxognisrcewbx2w ==A6roupjzpjx4gsy6rn9myuxanrb2dufwkynpmqreqdbfd9nlng /J> > HW
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;l = [(' B ', 2), (' A ', 1), (' C ', 3), (' d ', 4)] >>>import operator >>>l.sort (Key=operator.itemgetter (1)) >>>l >>>[(' A ', 1), (' B ', 2), (' C ', 3), (' d ', 4)] Example 6: (DSU method: Decorate-sort-undercorate) Copy Code code as follows: >>>l = [(' B ', 2), (' A ', 1), (' C ', 3), (' d ', 4)] >>>a = [(x[1],i,x) for i,x in Enumerate (L)] #i can confirm the stable sort >>>a.sort () >>>l = [s[2] for s in A]
) Returns an integer iteration that uses a parameter (stop) to range from 0 to stop-1, with two parameters (start and stop), and the range of iterations from start to Stop-1, and three parameters when using the value of the Iteration substring range from start to stop-1, interval step between each two values Reversed (i) Returns an iteration in which the iteration is reversed from the returned item in the Iteration child I Sorted (I, key, reverse) Returns the
fault (core dumped)Segmentation faultRegister Dump:eax:00000000 Ebx:00fb3ff4 ecx:00000002 edx:00000000Esi:080484e5 edi:080484e0 ebp:bfb7ad38 esp:bfb7ad0ceip:00ee806a eflags:00010203cs:0073 ds:007b es:007b fs:0000 gs:0033 ss:007btrap:0000000e error:00000007 oldmask:00000000ESP/SIGNAL:BFB7AD0C CR2:080484E0BackTrace:/LIB/LIBSEGFAULT.SO[0X3B606F]??: 0 (??) [0xc76400]/lib/tls/i686/cmov/libc.so.6 (__libc_start_main+0xe6) [0xe89b56]/build/buildd/eglibc-2.10.1/csu
:00fb3ff4 ecx:00000002 edx:00000000Esi:080484e5 edi:080484e0 ebp:bfb7ad38 esp:bfb7ad0ceip:00ee806a eflags:00010203cs:0073 ds:007b es:007b fs:0000 gs:0033 ss:007btrap:0000000e error:00000007 oldmask:00000000ESP/SIGNAL:BFB7AD0C CR2:080484E0BackTrace:/LIB/LIBSEGFAULT.SO[0X3B606F]??: 0 (??) [0xc76400]/lib/tls/i686/cmov/libc.so.6 (__libc_start_main+0xe6) [0xe89b56]/build/buildd/eglibc-2.10.1/csu/. /sysdeps/i386/elf/Start. s:122 (_start) [0x8048351]Memory M
Overview: share a function module that defines an output multi-list element.1. First create a folder for the templateEdit the nester.py file with the following content:def print_lol(the_list): forin the_list: if isinstance(each_item,list): print_lol(each_item) else: print(each_item)2. Create a file named "setup.py" in the new folderThe source code is as followsfromimport setupsetup( ‘nester‘, ‘1.0.0‘, py_moudles = [‘nester‘], ‘cs
key, the original order is preserved.Notice that two blue records remain in their original order, so (' Blue ', 1) must be before (' Blue ', 2).This awesome property allows you to sort through a series of sorts. For example, the student data is first sorted by grade ascending, and then by age descending, prioritizing age, and then sorting by grade:The timsort algorithm used by Python can effectively take advantage of the order that is already in the data set, so it can be efficiently ordered in
. sort (key = operator. itemgetter (1 ))>>> L>>> [('A', 1), ('B', 2), ('C', 3), ('D', 4)]Instance 6: (DSU method: Decorate-Sort-Undercorate)Copy codeThe Code is as follows:>>> L = [('B', 2), ('A', 1), ('C', 3), ('D', 4)]>>> A = [(x [1], I, x) for I, x in enumerate (L)] # I can confirm the stable sort>>> A. sort ()>>> L = [s [2] for s in A]>>> L>>> [('A', 1), ('B', 2), ('C', 3), ('D', 4)]In the preceding section, we use the List sorting method in Step
First, sort the list The recommended sort method is to use the built-in sort () method, which is the fastest and is a stable sortCopy the Code code as follows: >>> a = [1,9,3,7,2,0,5] >>> A.sort () >>> Print a [0, 1, 2, 3, 5, 7, 9] >>> A.sort (reverse=true) >>> Print a [9, 7, 5, 3, 2, 1, 0] >>> B = [' E ', ' A ', ' be ', ' ad ', ' dab ', ' DBC '] >>> B.sort () >>> Print B [' A ', ' ad ', ' Be ', ' dab ', ' DBC ', ' e '] The ordering of the list follows the
; Import operator>>> L. sort (key = operator. itemgetter (1 ))>>> L>>> [('A', 1), ('B', 2), ('C', 3), ('D', 4)] Instance 6: (DSU method: Decorate-Sort-Undercorate) The code is as follows: >>> L = [('B', 2), ('A', 1), ('C', 3), ('D', 4)]>>> A = [(x [1], I, x) for I, x in enumerate (L)] # I can confirm the stable sort>>> A. sort ()>>> L = [s [2] for s in A]>>> L>>> [('A', 1), ('B', 2), ('C', 3), ('D', 4)] In the preceding section, we use the List sorti
; L>>> [('A', 1), ('B', 2), ('C', 3), ('D', 4)]Instance 5:>>> L = [('B', 2), ('A', 1), ('C', 3), ('D', 4)]>>> Import operator>>> L. sort (key = operator. itemgetter (1 ))>>> L>>> [('A', 1), ('B', 2), ('C', 3), ('D', 4)]Instance 6: (DSU method: Decorate-Sort-Undercorate)>>> L = [('B', 2), ('A', 1), ('C', 3), ('D', 4)]>>> A = [(x [1], I, x) for I, x in enumerate (L)] # I can confirm the stable sort>>> A. sort ()>>> L = [s [2] for s in A]>>> L>>> [('A',
),('a',1),('c',3),('d',4)]>>>L.sort(lambda x,y:cmp(x[1],y[1])) >>>L>>>[('a', 1), ('c', 3), ('d', 4), ('b', 6)] Example 4: sort the second keyword >>>L = [('b',6),('a',1),('c',3),('d',4)]>>>L.sort(key=lambda x:x[1]) >>>L>>>[('a', 1), ('c', 3), ('d', 4), ('b', 6)] Instance 5: sort the second keyword >>>L = [('b',2),('a',1),('c',3),('d',4)]>>>import operator>>>L.sort(key=operator.itemgetter(1)) >>>L>>>[('a', 1), ('b', 2), ('c', 3), ('d', 4)] Instance 6: (DSU
,Y:CMP (x[1],y[1])) >>>L>>>[('a', 1), ('C', 3), ('D', 4), ('b', 6)] Example 4: Sort the second keyword>>>l = [('b', 6), ('a', 1), ('C', 3), ('D', 4)]>>>l.sort (key=LambdaX:x[1]) >>>L>>>[('a', 1), ('C', 3), ('D', 4), ('b', 6)] Example 5: Sort the second keyword>>>l = [('b', 2), ('a', 1), ('C', 3), ('D', 4)]>>>Importoperator>>>l.sort (Key=operator.itemgetter (1)) >>>L>>>[('a', 1), ('b', 2), ('C', 3), ('D', 4)] Example 6: (DSU method: Decorate-sort-under
This article mainly introduces the sorting methods of the dictionary (dict) and list (list) in Python. In summary, the built-in sort () method is preferred for sorting. For more information, see I. sort the list The recommended sorting method is the built-in sort () method, which is the fastest and stable. The code is as follows: >>> A = [1, 9, 3, 7, 2, 0, 5]>>> A. sort ()>>> Print[0, 1, 2, 3, 5, 7, 9]>>> A. sort (reverse = True)>>> Print[9, 7, 5, 3, 2, 1, 0]>>> B = ['e', 'A', 'be', 'AD', 'dab
Today, the efficiency is good, learned a lot of things, of which there are and check set, of course, I only learned a small part, but also need to do more to consolidate and practice.#include using namespacestd;classDisjointset {Private: int*father, *rank; Public: Disjointset (intsize) {Father=New int[size]; Rank=New int[size]; for(inti =0; i i) {Father[i]=i; Rank[i]=0; } } ~Disjointset () {Delete[] Father; Delete[] rank; } //Finding root Nodes intFind_set (intnode) { if(F
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