dex reverse number

#defineXX First#defineyy secondusing namespaceStd;typedefLong LongLl;typedefDoubleDB;Const DoubleEPS = 1e-6;Const intMAXN =400100; Mapint,int>Mp,mp2;mapint,int>:: Iterator It;pii A[MAXN];intB[MAXN]; LL FEN[MAXN];voidAddintNintk) { for(n N)) Fen[n]+=K;}int Get(intN) { intres =0; for(; n >0; N-= N (-N)) Res+=Fen[n]; returnRes;}voidrun () {intN; CIN>>N; REP (i,0, N) { intU,v;cin>>u>>v; if(!mp[u]) mp[u]=T; if(!mp[v]) mp[v]=v; inttemp =Mp[u]; Mp[u]=Mp[v]; MP[V]=temp; } intPre=1, nu

Merge and sort to obtain the number of reverse orders, and then obtain the maximum value between ANS-K and 0. You can also use a tree array. During the game, the posture may be incorrect. The tree array wa ,, Inversion Time Limit: 2000/1000 MS (Java/others) memory limit: 131072/131072 K (Java/Others)Total submission (s): 578 accepted submission (s): 249 Problem descriptionbobo has a sequence A1, A2 ,..., A

; intk=Left ; while(iRight ) { if(a[i]A[j]) t[k++]=a[i++]; Else{t[k++]=a[j++]; Ans+=mid-i+1; } } while(imid) T[k++]=a[i++]; while(jRight ) T[k++]=a[j++]; for(inti=left;i) A[i]=t[i];}voidMergeSort (intA[],intLeftintRight ) { if(leftRight ) { intMid= (left+right)/2; MergeSort (A,left,mid); MergeSort (A,mid+1, right); Mergearr (A,left,mid,right); }}intMain () {intA[m]; intN,i; while(SCANF ("%d", n) n!=0) {ans=0; for(intI=1; i) {scanf ("%d",A[i]); } mergesort (

The first topic is to reverse the integer, this problem is not difficult to achieve inversion, the main key point is how to make overflow judgment. Overflow judgment and then a string to an integer has been introduced, the subject of the third method, the number is converted to a string, using the method of string comparison size comparison.The code is as follows:1 classSolution {2 Public:3 intReversei

Poj 2299 Ultra-QuickSort (tree array/Reverse Order Number)Ultra-QuickSort Time Limit:7000 MS Memory Limit:65536 K Total Submissions:46080 Accepted:16763 DescriptionIn this problem, you have to analyze a particle sorting algorithm. the algorithm processes a sequence of n distinct integers by swapping two adjacent sequence elements until the sequence is sorted in ascendin

Https://www.nowcoder.com/acm/contest/77/ASteps:First, the array is discretized, the original array is sorted and renumbered into another arrayAnd then in the original order1) A little update of the tree array (because the elements of the tree array are mainly an array of elements of the and, in this case only the number of concerns, so the elements and direct statistics as the number and)2) A little bit to

Ultra-quicksort Time Limit: 7000MS Memory Limit: 65536K Total Submissions: 46080 Accepted: 16763 DescriptionIn this problem, you has to analyze a particular sorting algorithm. The algorithm processes a sequence of n distinct integers by swapping, adjacent sequence elements until the sequence is Sorted in ascending order. For the input sequence 9 1 0 5 4, Ultra-quicksort produces the output 0 1 4 5 9. Your tas

Link: http://codeforces.com/contest/459/problem/D D. pashmak and parmida's problemtime limit per test3 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard output Parmida is a clever girl and she wants to particle in Olympus Iads this year. Of course she wants her partner to be clever too (although he's not )! Parmida has prepared the following test problem for pashmak. There is a sequenceAThat consistsNIntegersA1 ,?A2 ,?...,?AN. Let's denoteF(L,?R,?X) The

=[[nsmutablestring Alloc]initwithformat:@"May 05, 2013"];2NSLog (@"The third question-------------");3NSLog (@"Original date:%@", STR3);4Nsrange RANGE1=[STR3 rangeofstring:@"years"];5 6[Str3 Replacecharactersinrange:nsmakerange (range1.location-1, range1.length+2) Withstring:@"-"];7Nsrange RANGE2=[STR3 rangeofstring:@"Month"];8[Str3 Replacecharactersinrange:nsmakerange (range2.location-1, range2.length+2) Withstring:@"-"];9Nsrange RANGE3=[STR3 rangeofstring:@"Day"];Ten[Str3 Replacecharac

Problem B: Ultra-QuickSortIn this problem, you have to analyze a particle sorting algorithm. the algorithm processes a sequence of ndistinct integers by swapping two adjacent sequence elements until the sequence is sorted in ascending order. for the input sequence 9 1 0 5 4, Ultra-QuickSort produces the output 0 1 4 5 9. Your task is to determine how swap operations Ultra-QuickSort needs to perform in order to sort a given input sequence. The input contains several test cases. Every test ca

integer that indicates the child's degree of upset and the minimum value.Sample input3 3 2 1Sample output9TipsFirst of all, exchange height of 3 and 2 children, and then exchange height of 3 and 1 children, and then exchange height of 2 and 1 children, each child's unhappy degree is 3, the sum of 9.The numbers in the array are first read into the tree array T1 to find the inverse point logarithm of each current point and the left point, and then the array is read into the tree array T2 to find

/********************************** Date: * Author: sjf0115 * question: 9 degrees 1064 * Title: reverse Number * Source: http://ac.jobdu.com/problem.php? PID = 1064 * result: AC * Meaning: * conclusion: * *********************************/# include

Merge Sorting Merge two ordered arrays P, mid 1 3 5 6 7 12 Q 2 4 6 8 9 11 If 3 is greater than 2, the values after 3 are greater than 2. Therefore, the number of reverse Orders of 2 is mid-p + 1. // 2299.cpp: defines the entry point for the console application. // # Include Using Namespace STD ;# define Max 500000 Int Arr [Max]; Int TMP [Max] ;__ int64 sum; Void Merge ( Int Le, Int Mi,Int

Else returnCalc (sum (lp,l,mid), SUM (rp,mid+1, R)); - } Wu - intMain () { About intT; $ while(SCANF ("%d", n)! =EOF) { - for(inti =1; I "%d",A[i]), a[i]; -Build_tree (1,1, n); - A intAns =0; + for(inti =1; I ){ theAns + = SUM (1, a[i]+1, n); Update (1, A[i],1); - //printf ("ans =%d\n", ans); $ } the the intres =ans; the for(inti =1; I ){ theAns + = n2*a[i]-1; -res =min (res,ans); in //p