hackerrank alternatives

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Make the most (Hackerrank Codeagon)

attended by up to a total.If m=1, of course, according to the end time sort, can.Here, simply deform, set b[j] for the point where the J-person is currently located (initially 0), for the first meeting, if there are more than one person to meet the criteria, select B[j] the largest one.Attached code:1#include 2#include 3#include 4#include 5#include 6 using namespacestd;7 8typedef pairint,int>PII;9 #defineF FirstTen #defineS Second One A intMain () { - intN, P; -scanf"%d%d", n, P); thePII t

hackerrank# Hexagonal Grid

]; - BOOLU[max_n]; - BOOLD[max_n]; the - intMain () { - /*Enter your code here. Read input from STDIN. Print output to STDOUT*/ -CIN >>T; + while(t--) { -CIN >>N; + Amemset (U,0,sizeof(U)); atmemset (D,0,sizeof(d)); - for(inti =0; i ) { - CharC; -CIN >>C; -U[i] = c = ='0'?true:false; - } in for(inti =0; i ) { - CharC; toCIN >>C; +D[i] = c = ='0'?true:false; - } the *Memset (CAN,0,sizeof(Can)); $ for(inti =0; I 2; i++)

Hackerrank-"The longest increasing subsequence"

It requires O (NLGN) solution. And actually I think the passing code is for "Non-decreasing".#include #include#include#include#includestring>#include#includeusing namespacestd;intMain () {intT CIN >>T; Vectorint>arr (t); for(inti =0; I ) Cin>>Arr[i]; Vectorint> dp (t,1); //C[i]: Smallest last elem of a LIS seq with lenghth ivectorint> C (1, arr[0]); intRET =1; for(inti =1; I ) { if(Arr[i] 0]) {c[0] =Arr[i]; Dp[i]=1; } Else if(Arr[i] >=C.back ()) {C.push_back (arr[i]

Hackerrank-"Stock maximize"

must be a O (n) solution, and there is. What's better than a standard DP in cerntain cases? Greedy.#include #include#include#includeusing namespacestd;#defineREP (i, S, N) for (int i = s; i typedefLong LongLL; LL Calc (Vectorinch) {size_t len=inch. Size (); LL ret=0; Std::reverse (inch. Begin (),inch. End ()); LL Peak= -1; REP (i,0, Len) { if(inch[I] >Peak) {Peak=inch[i]; } Else{ret+ = peak-inch[i]; } } returnret;}intMain () {intT CIN >>T; while(t--) { intN CIN >>

Hackerrank-"Red John is Back"

1AC. 1D DP + sieving#include #include#include#include#include#include#includestring>#include#include#include#includeusing namespacestd;intWaysintN) { if(N 1)returnN; Vectorint> dp (n +1,0); dp[0] =1; for(inti =0; I ) {Dp[i+1] +=Dp[i]; if((i +4) 4] +=Dp[i]; } returndp[n];}intCntprimes (intN//sieving{vectorint> Mark (N,1); mark[0] =0; intInx =1;//2 intSCNT =1; while(Inx 0) {scnt=0; for(inti =2* Inx +1; I 1) ) {Mark[i]=0; SCNT++; } if(Scnt >0) {Inx++; while(Inx 0) inx++; } }

Hackerrank-"The Coin Change Problem"

If coin Order matters, that's, each sequence are unique, the DP function is a simple enough-to-make it 1D DP. But the key is this order doesn ' T matter, so we need to add one more state:ending coin. And for each DP advance step, we only put >= coins.#include #include#include#includeusing namespacestd;typedef unsignedLong LongULL;intMain () {unsigned n, m; CIN>> N >>m; VectorV (m); for(Unsigned i =0; I ) Cin>>V[i]; Std::sort (V.begin (), V.end ()); //dp[val][ending Coin]Vector1, Vector0)); d

"Enumeration approximate" Hackerrank-week of Code 26-satisfactory Pairs

Test instructions: Give you a positive integer n, ask how many positive integers you exist on a, B (aThe approximate number of all the numbers within N is preprocessed, then the violent enumeration A, the violent enumeration of X, and then enumerates all the n-ax, the sentence weight, the statistical answer can be.#include "Enumeration approximate" Hackerrank-week of Code 26-satisfactory Pairs

Fixed logarithm of HackerRank Algorithms-Search-Pairs Array

I made a few questions in HackerRank, so let's talk about it... Question: Give n and k, then give n numbers, and find the number of k pairs in the array. Where [N /* * Author: illuz

Alternatives command usage

Alternatives command usage Alternatives is a powerful command in Linux. It can only run under the root permission. If the system has several commands with similar functions but cannot be deleted at will, you can use alternatives to specify a global setting.Alternatives is often used to install multiple versions of the same software on the same system. For example

Alternatives command usage

Alternatives command usage Alternatives is a powerful command in Linux. It can only be executed under the root permission. If the system has several command functions that are similar but cannot be deleted at will, you can use alternatives to specify a global setting. Alternatives is often used to install multiple vers

Ubuntu update-alternatives (soft connection management), ubuntualternatives

Ubuntu update-alternatives (soft connection management), ubuntualternatives Update-alternatives-manage soft connections/character links (symbolic links) Command Format Update-alternatives [options] command Detailed description Update-alternatives can be used to create, delete, repair, and soft connections. It c

update-alternatives command Explanation

Reprint: http://blog.csdn.net/maixia24/article/details/11707289Update-alternatives is a tool dedicated to maintaining the system command link in the Ubuntu system, which makes it easy to set which command the system uses by default, which software version, for example, we have both open jdk and Sun JDK Two versions installed in the system. And we want the system to use the sun JDK by default, what should we do? Through the update-

Red Hat under alternatives command usage

Alternatives is a powerful command under Linux. Can only be performed under root permissions. If there are several commands in the system that are very similar, but cannot be deleted at will, then you can use alternatives to specify a global setting. Alternatives is often used to install multiple versions of the same software in the same system. For example, in

Update-alternatives command

Update-alternatives command 1. Functions Update-alternatives is a dpkg utility used to maintain symbolic links of system commands to determine which commands are used by default. In the Debian system, we may install many similar programs and optional configurations at the same time, such as the web browser program (Firefox, Konqueror), Window Manager (wmaker, metacity) different theme from that of the mo

Ubuntu update-alternatives

Update-alternatives is a tool dedicated to maintaining the system command link in the Ubuntu system, which makes it easy to set which command the system uses by default, which software version , for example, we install both open jdk and sun in the system JDK two versions, and we want the system to use the sun JDK by default, what to do? Through the update-alternatives can be very convenient to achieve.sudo

Linux Alternatives Command detailed

Alternatives is a powerful command under Linux. Can only be performed under root authority. If there are several command functions in the system that are very similar, but can not be arbitrarily deleted, then use alternatives to specify a global setting.Alternatives is commonly used to install multiple versions of the same software on the same system. For example, in order to develop the need, I need to ins

Update-alternatives command

Update-alternatives is a script for switching between multiple commands of the same type and can be installed in Debian via the Apt-get install dpkg. Before explaining the details of Update-alternatives, let's take a look at the examples already in the system. Open the terminal and execute the following command:LsResults: lrwxrwxrwx 1 root root 2011-03-12 15:20/usr/bin/java-/etc/

Hackerrank-play with words

Kinda similar with another palindrome DP from Leetcode. Feel it, it is a bottom-up dp-palindrome subsequence.str =input () Slen=Len (str) DP= [[0 forXinchRange (Slen)] forXinchrange (Slen)] forCleninchRange (1, Slen + 1): forIinchRange (0, Slen-clen + 1): ifClen = = 1: Dp[i][i]= 1elifClen = = 2: Dp[i][i+ 1] = 2ifStr[i] = = Str[i+1]Else1Else: ifStr[i] = = Str[i + clen-1]: Dp[i][i+ Clen-1] = dp[i + 1][i + clen-2] + 2Else: Dp[i][i+ clen-1] = max (dp[i + 1][i + clen-2], dp[

Hackerrank "Equal Stacks"

Greedy-though Simple, but fun!#include #includeusing namespacestd;intMain () {intN1; intN2; intN3; CIN>> N1 >> n2 >>N3; Long LongL1 =0, L2 =0, L3 =0; Vectorint>H1 (N1); for(intH1_i =0; H1_i ) {cin>>H1[h1_i]; L1+=H1[h1_i]; } Vectorint>H2 (N2); for(intH2_i =0; H2_i ) {cin>>H2[h2_i]; L2+=H2[h2_i]; } Vectorint>H3 (N3); for(intH3_i =0; H3_i ) {cin>>H3[h3_i]; L3+=H3[h3_i]; } intI1 =0, I2 =0, i3 =0; while(! (L1 = = L2 L2 = =L3)) { //which stack is highest now? intMaxi =1; intM

Hackerrank-[Algo] Matrix Rotation

(1, CC, 1): - # Down ins[(rr-1 + i) * m + (j + i)] = (rr-1 + i) * m + (j-1 +i) - forJinchXrange (Rr-2,-1,-1): to # Right +s[(j + i) * m + (cc-1 + i)] = (j + 1 + i) * m + (cc-1 +i) - forJinchXrange (Cc-2,-1,-1): the #Top *S[i * m + (j + i)] = i * m + (j + 1 +)i) $i + = 1Panax Notoginseng returns - the defMultiply (A, b): +n =Len (a) Ac = [] the forIinchxrange (n): + c.append (A[b[i]) - returnC $ $ defDisplacepow (A, k): -

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