hadoop hql

no repeated elements in the Set, the values of username and password cannot be the same. Change hql to string hql = "select new set (name, passwd) from users "; 7. Modify the default query result (query. List (). The result is not returned in the form of an object [] array and is returned in a custom type. Custom class: package COM. domain; // Query. in the list (), the default object array is

@OverridePublic listTODO auto-generated Method StubListString hql= "fromCurrency where code like:code and desc1 like:d ESc1";Query query = this.getsession (). CreateQuery (HQL).setString ("code", "%" +code+ "%"). SetString ("Desc1", "%" +desc1+ " % "). Setfirstresult (offset). Setmaxresults (size);List = Query.list ();return list;}HQL the value of the reference b

Where clauseFilter the selected results to narrow down the selection range. If you do not name an alias for a persistent instance, you can directly use the attribute name to reference the attribute: From person where name like 'Tom %' The preceding hql statement has the same effect as the following statement: From person as P where P. name like 'Tom %' The composite attribute expression enhances the WHERE clause function, for example: Fro

One, hql a pair of multi-queryClass (1) (multi) Students/** * Implementation of classes and student internal connection * * SELECT c.*,s.* * FROM classes C INNER JOIN student S * WHERE (C.CID=S.CID) */@Testpublic void Testinnerjoin () {session = Hibernateutils.opensession (); Query query = Session.createquery ("from Classes C" + "INNER join c.students S"); List List = Query.list ();//object[]session.close ();} /** * Urgent Internal connection */@Testp

In NHibernate HQL can help us to turn into the final dependent database query script;Syntax is also very strong, suitable for the mainstream database, HQL does not support union, to take multiple table data can do two separate queries.IQuery query = nhibernatehelper.opensession () . CreateQuery ( @ "select p from Product as p,product as pp where p.nam

Org. hibernate. hql. ast. QuerySyntaxError: user is not mapped. [from user as u where u. userid =?] This problem occurs mainly because the hibernate statement is incorrect. User. hbm. xml: Therefore, the hql statement is as follows: String hql = "from User as u where u. userid =? "

Java hql case-when usageif (null = = Sorter) { hql.append ("ORDER by m.mdate desc,case if m.mealtime = ' Morning ' then ' 1 ' when m.mealtime = ' Noon ' Then ' 2 ' when m.mealtime = ' Night ' and ' 3 ' when m.mealtime = ' midnight ' then ' 4 ' End '); } Note:The meaning of the above HQL statement can be understood as:By mdate descending order, but also to meet when mealtime = ' morning ',

object is more expensive, it is generally recommended to use singleton mode)Then, create an action object that can be used at the user level through the session.Open Transaction Object trans = session. BeginTransaction ();The idea above and the SQL Server we used to use is a truth. Next look at the difference: When we used to deal with databases, we usually use SQL statements and then manipulate the database directly. and All operations in NH (increase and revise) All for" object ", If

Scenario Overview:I encountered such a problem in development:System and User relations: A user can belong to multiple systems, a system can have multiple users Data structure: syssystem-system table, representing different system sysuser-user table, representing the user, attribute systems describes the Many-to-many relationship sys_user_system-relational table (not embodied as entity Class) when the business logic is: Query a system under the user name contains "xbz" user, his

Publiclistgetorgan (stringorgancode,stringorganname) { Stringhsql; Listlist; if (Organcode!=nullorgancode.length () > 0) { hsql= "fromab31where bae002=?andaab061like? "; list=gethibernatetemplate (). Find (hsql,new object[]{organcode, '% ' +organName+ '% ' }); } else{ hsql= "FROMNBSP;AB31NBSP;WHERENBSP;AAB061NBSP;LIKENBSP;?"; list=gethibernatetemplate (). Find (Hsql, '% ' +organName+ '% '); } returnlist;} Public List Getorgan (string organcode, String organname) { string hsql; Lis

In the HQL statement, you cannot use limit to limit the number of bars that are displayed. For example: From User_info ORDER BY createdtime desc LIMIT 1 The number shown is not 1, but the number of bars you have queried, so the above notation is wrong. How to solve the limit in HQL can not be used, and set the number of queries out of the collection, we should use the Setmaxresults (e) method to solve

select name,age,user_id from T_user JPQL: Object-oriented JPQL statements Analysis:The first statement is used to execute a query against the T_user table tables, querying the name, age, and user_id three data columns;The second statement is used to execute a query against the user entity, querying the name, age, and UserId properties of the user entity.Third, HQLHQL (Hibernate query Language) is an object-oriented query, followed by a "table name", where the condition is followed by "fields i

.*;import org.hibernate.*;import org.hibernate.cfg.*;p ublic class Test {public static void main (string[ ] args) {//Here is the so-called establishment transaction session Session=new Configuration (). Configure (). Buildsessionfactory (). Opensession (); Transaction transaction=session.begintransaction (); TestTable testtable=new testtable (); listThe central idea of the entire file is to use the HQL statement to convert the query resu

Label:Question: How do I use MySQL functions in hibernate? 1.hibernate supports the original SQL statement query, using Session.createsqlquery () to create query objects; 2. How do I use the MySQL function in hql? You need to redefine Hibernate's dialect (dialect) to register your needs; The concept of a dialect (dialect) is mentioned here: 　　Hibernate is still using SQL statements to perform database operations, although all relational databases supp

production environment Hadoop large cluster fully distributed mode installation 2013-3-7 Installation Environment Operating platform: Vmware2 Operating system: Oracle Enterprise Linux 5.6 Software version: Hadoop-0.22.0,jdk-6u18 Cluster Architecture: Node,master node (hotel01), slave node (hotel02,hotel03 ...) Host name IP System version

There's a friend in the group. To solve a problem, high score for a HQL multiple query statement. For a description of the problem, see http://topic.csdn.net/u/20090621/16/4eac6fe0-bf3e-422e-a697-f7584732f66e.html, as follows: A discipline table (Field), a user table (users), many-to-many relationships. Subject table has two fields, ID and Descripiton, User table has many fields, not listed Set set in field with users Set set fields in user Now

Using the HQL statement to complete the insert operation is not possible, whether you use the Insert Into....values ... or insert Into.....select ..... No, because Hibernate's HQL language is used for object-oriented query functionality, but there is no query action involved in the insert operation, so HQL cannot be used for INSERT statements, while Select, Upda

(cachestore.java:90)At Com.agileeagle.webgame.game.service.imp.CacheStore.updateEntityList (cachestore.java:120)At Com.agileeagle.webgame.framework.cache.AbstractPersistCache.persist (abstractpersistcache.java:432)At Com.agileeagle.webgame.game.cache.imp.UnionCache.persist (unioncache.java:515)At Com.agileeagle.webgame.game.debuggameserver$debugthread.persist (debuggameserver.java:150)At Com.agileeagle.webgame.game.debuggameserver$debugthread.run (debuggameserver.java:66)2015-03-19 14:16:29,296

Chapter 1 Meet HadoopData is large, the transfer speed is not improved much. it's a long time to read all data from one single disk-writing is even more slow. the obvious way to reduce the time is read from multiple disk once.The first problem to solve is hardware failure. The second problem is that most analysis task need to be able to combine the data in different hardware. Chapter 3 The Hadoop Distributed FilesystemFilesystem that manage storage h

PackageCom.hfview.bean;ImportJavax.persistence.Column;Importjavax.persistence.Entity;ImportJavax.persistence.Id;Importjavax.persistence.Table;@Table(name ="T_card", schema="ZHW")@Entity Public class Card { PrivateString ID;PrivateString cardId;PrivateString area;@Id @Column(name="ID") PublicStringgetId() {returnId } Public void setId(String ID) { This. id = ID; }@Column(name="CARDID") PublicStringGetcardid() {returnCardId; } Public void Setcardid(String cardId) { This. cardId = CardId; }