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Topic 1372: Maximum sub-vectors and (maximum and duration of contiguous subarray) time limit: 1 seconds Memory limit: 32 Mega Special: No submission: 2169 Resolution: 570 Topic Description: Hz occasionally take some professional questions to confuse those non-computer majors. Today JOBDU Test team after the meeting, he said again: in the Ancient one-dimensional pattern recognition, it is often necessary to calculate the maximum sum of continuous sub-vectors, when the vector is all positive, the

Title: Enter an array of integers to implement a function to adjust the order of the numbers in the array, so that all the odd digits are in the first half of the array, all the even digits are in the second half of the array, and the relative positions of the odd and odd, even and even are constant. Public voidReorderarray (int[] Array) { for(inti = 0; i ) { intIndexeven = 0; BooleanFlageven =false; for(intj = 0; J ) { if((Array[j] 1) = = 1) { if(flageven)

Title One: Find the duplicate numbers in the array. 。。。。。。 S2。。。。。1 classSolution {2 Public:3 //Parameters:4 //numbers:an array of integers5 //length:the length of array numbers6 //duplication: (Output) The duplicated number in the array number7 //Return Value:true If the input is valid, and there be some duplications in the array number8 //otherwise false9 BOOLDuplicateintNumbers[],intLengthint*duplication) {Ten if(numbers = = nullptr | | length 0){ One

Title: The Age of a company (0-99) is ranked, the total number of people in the company is tens of thousands of. Requires a time complexity of O (n), which can assist in the space of O (n).Idea: the implementation function is void sortage (int ages[],int len). The auxiliary space is an integer array timesofage[100], which is used to store the number of people per age (when the I#include The order of the age of the second chapter of the sword offer-

Interview three: Finding element problems in two-dimensional arrayspublic static void Main (string[] args) {int[][] num = {{1,2,8,9},{2,4,9,12},{4,7,10,13},{6,8,11,15}};Search (num,7);}public static void Search (int[][] arr,int target) {int rows = Arr.length;int columns = Arr[0].length;int row = 0;int column = Columns-1; while (rowif (Target==arr[row][column]) {System.out.println (target+ "in" +row+ "line," +column+ "column");Break}if (Target>arr[row][column]) {row++;}if (Targetcolumn--;}}}Inter

Title Description:moves the first element of an array to the end of the array, which we call the rotation of the array. Enter a rotation of a non-decreasing array, outputting the smallest element of the rotated array. For example, the array {3,4,5,1,2} is a rotation of {1,2,3,4,5}, and the minimum value of the array is 1. Note: All elements given are greater than 0, and if the array size is 0, return 0. Problem Solving Code:functionMinnumberinrotatearray (rotatearray) {//Write code here if(Ro

https://www.nowcoder.com/practice/d8b6b4358f774294a89de2a6ac4d9337?tpId=13tqId=11169rp=1ru=% 2fta%2fcoding-interviewsqru=%2fta%2fcoding-interviews%2fquestion-rankingtpage=1 Test instructions Two lists are lined up, to merge them together analyze make a predecessor node point to the first node dummycur point to dummy code/*public class ListNode { int Val;listnode next = null;listnode (int val) {this.val = Val;}}*/public class Solution {public ListNode Merge (listnode list1,listnode list2) { list

{TenK = i;//record the current location Onecount++; A } - Else - { thecount--;//different counter minus 1 - if(Count = =0) - { -Count =1; +K =i; - } + } Ai++; at } - if(count) - { -Count =0; - for(i=0; i) - { in if(arr[k]==Arr[i]) -count++; to } + if(count>len/2) - returnArr[k]; the Else * retur

Title DescriptionIn a two-dimensional array, each row is ordered in ascending order from left to right, and each column is sorted in ascending order from top to bottom. Complete a function, enter a two-dimensional array and an integer to determine if the array contains the integer.Topic links Thinking of solving problems Consider each row as an array of sequential increments, using 二分查找 , by iterating through each row to get answers, the time complexity is NLOGN Public class solu

The title description enters an array of integers, implements a function to adjust the order of the numbers in the array, so that all the odd digits are placed in the first half of the array, all the even digits are located in the second half of the array, and the relative positions between the odd and odd, even and even are guaranteed. Two traversal ...classSolution { Public: voidReorderarray (vectorint> Array) {Vectorint>tmp; intLen =array.size (); for(inti =0; i ) {

{ return true; } } }} Public classMain { Public Static voidMain (string[] args) {intA = 16; int[] Array = {}; Solution So=Newsolution (); System.out.println (So. Find (16, array)); }}classSolution { Public BooleanFind (intTargetint[] Array) { for(inti = 0; i ) { intL = 0; if(array.lengthreturn false; if(array[0].lengthreturn false; intr = Array[0].length-1; while(lr) {intMid = (l+r)/2; if(target>Array[i][mid]) {L= Mid+1; } Else if(targ

"Sword refers to offer" with two stacks to achieve the queue problem-solving report (Python) tags (space-delimited): Leetcode Topic Address: Https://www.nowcoder.com/ta/coding-interviews topic Description: Implement a queue with two stacks to complete the push and pop operations of the queue. The elements in the queue are of type int. Ways The first stack temporarily saves the inserted data, and when the pop-up function is invoked, it pops up dire

discussing: (1) We need to consider how to tell a function that the caller's input is not valid when the input array or length is invalid. There are several common methods of dealing with invalid input, which are discussed in detail in the 17th question of this blog series. (2) The premise of this algorithm is that the input array does contain a number that appears more than half the length of the array. If the array does not contain such a number, then the input is also invalid. So I added a p

* We include only factor 2,3, and 5 is called the ugly number. Find the 1500th ugly number in order from small to large. For example, 6, 8 are ugly, but 14 is not because it contains factor 7. We used to think of 1 as the first ugly number * This procedure includes the general method and the optimal method. The contribution of this blog is to use Java to achieve the sword refers to the offer face test questions 34: Ugly number.Related explanation here

.cursum>maxsum.maxsum = 7.Handle number 4th subscript: Add -2.cursum = 7-2 = 5.maxSum = 7 (unchanged)Handle number 5th subscript: plus 5.curSum = 5+5 = 10.cursum>maxsum.maxsum = 10.Handle number 6th subscript, plus -4.cursum = 6.maxSum = 10 (invariant).Therefore the largest and is 10. Code implementation: int findmaxsum (int arr[],int n) { assert (arr n); int cursum = 0; int maxsum = 0; for (int i = 0; i We know that the written program must have a certain degree of fault tole

, companies have no time to wait for college graduates to fill this demand. They need help now, so many people are turning to the so-called "new job", a term that refers to working-class workers who do not need a college degree but need to attend training. This approach is a desperate practice for major companies to combine traditional college recruiting and cooperative education. In a September report, MSNBC highlighted this growing group of people trained to work on specific blockchain develop

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I need A offer!Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 18054 Accepted Submission (s): 7237Problem descriptionspeakless very early want to go abroad, now he has finished all the required examinations, prepared all the materials to prepare, so, they need to apply for school. To apply for any university abroad, you have to pay a certain amount of application fees, which is very alarming. Speak

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I need A offer!Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 18268 Accepted Submission (s): 7317Problem descriptionspeakless very early want to go abroad, now he has finished all the required examinations, prepared all the materials to prepare, so, they need to apply for school. To apply for any university abroad, you have to pay a certain amount of application fees, which is very alarming. Speak