SELECT * FROM table WHERE convert (Nvarchar, DateAndTime, 111) = CONVERT (Nvarchar, GETDATE (), 111) ORDER by DateAndTime DESCRecord of the Month
SELECT * FROM table WHERE DateDiff (Month,[dateadd],getdate ()) =0
Week
This is the SQL script that calculates the first day of the one month:SELECT DATEADD (mm, DATEDIFF (Mm,0,getdate ()), 0)--the first day of the monthSELECT DATEADD (mm, DATEDIFF (Mm,0,getdate ())-1, 0)-the first day of the monthSELECT DATEADD
JS Get Current date time + date validation + judgment leap Year + date difference + date formatting +js Judging How many days a certain monthString to date type +js current datetime + date validation + judgment leap Year + date difference + date
Original link: http://www.jb51.net/article/44468.htm
First, get the last day of the month (possibly 28/29/30/21) problem, the idea is simply to get the first day of the next month, the number of milliseconds from 1970, and then subtract the number
/**
* determine how many days a certain month of a year
* @return [Type][description]
*/
function DaysInMonth ($year = ', $month = ') {
if (empty ($year)) $year = Date (' Y ');
if (empty ($month)) $month = Date (' m ');
if
title page
function Getlastday (year,month)
{
var new_year = year; Take the current year
var new_month = month++;//Remove the first day of one months to facilitate calculation (last day is not fixed)
if (month>12) //If
PS: After learning Regular Expressions for so long, I didn't make any decent patterns. I woke up early and came up with a whimsy, I made up my mind to prove that my regular expression is not white-so I chose the most common date match ......
How do I calculate the day of the week? --Caille (Zeller) formulaWhat is the day of the week in history? What day of the week is the future? There are a number of computational formulae (two general calculation formulae and some piecewise
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