how to find soundex number

Label: style blog color Io AR for SP Div Problem: Given an array of integers, every element appearsTwiceCould t for one. Find that single one. Note: Your algorithm shocould have a linear runtime complexity. cocould you implement it without using extra memory? Analysis: The number in the array appears only once, and the number appears twice, To

Enter an ordered array and a number to find two numbers in the array so that they are exactly the number entered. If there are many pairs of numbers and equals the input number, the output can be any pair. For example, input arrays 1, 2, 4, 7, 11, 15, and number 15. Because

In the C ++ array, a number appears more than half the length of the array. Find this number. (NIU kejian refers to offer) //////////////////////////////////////// ///////////////// The number of occurrences of a number in the array exceeds half of the length of the array,

I went to interview an iPad development company the other day. The first question was to find a duplicate number in 1000 (1-999. The 1000 numbers are sequential and out of order. My first reaction is to create an array of 999, and then find the corresponding array subscript based on the number. If it is null, it is fil

PackageShuzu;/** Enter an array that has been sorted in ascending order and a number * Find two numbers in the array so that their sum is the number entered, requiring a time complexity of O (n) * If there are many pairs of numbers and equals the input number, the output can be any pair. */ Public classDemo1 {Private S

If there is a number in the array that appears more than half the length of the array, find this number. For example, enter an array of length 9 {1,2,3,2,2,2,5,4,2}. Since the number 2 appears in the array 5 times, which exceeds half the length of the array, the output is 2. #include If there is a

Problem: To determine the number of user input, or the value of a parameter of a method in a program, or whether the value of a variable is in a heap number.Concise notation: Put the heap number in the list, using the list's contains () method to check whether the list contains this number, reverse.The code is as follows: Static voidMain (string[] args) {Console.

Title Link: http://acm.hdu.edu.cn/showproblem.php?pid=1394Understand the merger sort, learn a bit of other people's blog, have the topic to knock over ...This problem I use merge sort is I currently the fastest algorithm 62ms ... Of course, in my blog There are also wired and tree arrays to find the reverse number of the template;Here I do not discretization, but not all the reverse

Common:I am always used to call the common law, because I really can not find a proper name to describe it, in fact, is the simplest way, a little program based on the people are able to think, that is the SHIFT + count, very simple, not much to say, directly on the code, this method of operation of the number of input n is the highest bit 1 of theintBitcount (unsignedintN) {unsignedintc =0;//counter wh

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Topic address The main idea: S (n) is the sum of the true factors of n of positive integers, a factor that is less than n and divisible by n, such as S (12) =1+2+3+4+6=16. If any number m,s (m) is not equal to N, then it is said that N is a non-touch number, and that the number within 1000 is not a number. To solve the

Label: A circle contains a finite number of vertices. A straight line does not pass through any point and equals all vertices.Consider this problem from outside the circle.Randomly find a straight line l that is separated from the circle, and then draw a straight line between each two points to mark the intersection with L (if parallel, ignore ), then start to rotate L with any unlabeled point on L as the c

#include First to find the maximum value, and then use the maximum value to go down to try to be at least two number of approximate, the method is to sift up the 　　[BC] To find the number of any two number of conventions in the array, and to take maximum value in many case

Given an integer, outputs the number of 1 in the binary representation of this integer. For example, given an integer of 7, in which the binary is represented as 111, the output is 3.The problem can be done with bit operations.Idea: First, to determine whether the last digit of this number is 1, if 1, then the Counter plus 1, and then move right to discard the last one. Loop through the operation until the

Find in a two-dimensional array, the young matrix in a two-dimensional array, each row is ordered in ascending order from left to right. Each column is sorted in ascending order from top to bottom. Complete a function, enter an array and a number to determine if the array contains this number # include Copyright NOTICE: This article for Bo Master original articl

Find the number of 1 in a binary binary:General Method :#include #include int count_one_bits (unsigned int value){int count = 0; for (int i = 0; i {if (value 1 = = 1) (%2 equivalent to 1) {count++;}value = value >> 1; (move right one equivalent to 2)}return count;}int Main (){unsigned int value= 0;scanf ( "%d" , value);int ret = count_one_bits (value);printf ( "%d\n" , ret);System ( "pause" );return 0;}6

First, the required number of qualitative factorization, and then the power of the various factors plot no, such as 600 = 2^3 * 3^1 * 5^2 So the number of factors is (3+1) * (+) * (2+1) = 24 Public classtestyuman{ Public Static voidMain (string[] args) {intRes=get_factor (6); System.out.println (RES); } Public Static intGet_factor (intinput) { intfactor=1,num=input; for(inti=2;i)//Note the ra

In an array, a number appears more than half the total length of the array element, and the number is found. Package com.threeTop.www; /** * Find more than half of the elements in the array * @author wjgs * * * /Public class Morethanhalf { /** * O (N) Time complexity solution * @param array * /public static void

Given a number 'n', find the smallest number 'P' such that if we multiply all digits of 'P', we get 'n '. the result 'P' shoshould have minimum two digits. Examples: Input: n = 36Output: p = 49 // Note that 4*9 = 36 and 49 is the smallest such numberInput: n = 100Output: p = 455// Note that 4*5*5 = 100 and 455 is the smallest such numberInput: n = 1Output:p = 1

#include This article from "Thanksgiving" blog, reproduced please contact the author! Only one number appears once in a set of data. All other numbers appear in pairs. Please find out the number. (using bitwise operations)