hungarian dolls

Hungarian naming convention Naming rules for MFC, handles, controls, and structures Windows Sample Variables MFC class Sample Variables Hwnd Hwnd; Cwnd * Pwnd; Hdlg Hdlg; Cdialog * Pdlg; HDC HDC; CDC * PDC; Hgdiobj Hgdiobj; Cgdiobject * Pgdiobj; Hpen Hpen; Cpen * Ppen; Hbrush Hbrush; Cbrush * Pbrush; Hfont Hfont;

There are m girls and N boys. If boys and girls have a crush on each other, they will be connected and asked how many pairs can be matched. This blog post is well written and does not contain daunting graph theory terms. Http://blog.csdn.net/dark_scope/article/details/8880547 The core idea is the word "Teng". It doesn't matter if you don't have a sister. Let the old ones change their favorite sister to see if they can "Teng" their favorite sister. 1 //#define LOCAL 2 #include Code Jun HDU 206

This is a list of Visual Basic controls provided by the subject and the first part of the object for the use of consistent Hungarian notation. This clear help helps standardize the Graphic Style and the graphic structure of the application. Object Prefix Example--------------------------------------------------------------------------Form frm frmFileOpenCheck bo

Http://www.cnblogs.com/pony1993/archive/2012/07/25/2607738.html1#include 2#include 3#include 4 5 using namespacestd;6 Const intn=1001;7 intn1,n2,k;8 //N1,n2 is a set of vertices with a two-point graph, where x∈n1,y∈n29 intMap[n][n],vis[n],link[n];Ten //Link records the number of X points that match the point y in the N2 in N1 One A intFindintx) - { - inti; the for(i=1; i) - { - if(Map[x][i]!vis[i])//X->i has edges, and node i is not searched - { +vis[i]=1;//tag node

algorithm. (Augmenting Path algorithm)Input:An x-y bigraph g, a matching M in G,And the set U of m-unsaturated vertices in X. Idea :Explore m-alternating paths form U,letting S? X and T? Y be the sets of vertices reached.Marks vertices of S that has been explored for path extensions.as a vertex is reached, the record of the vertex from which it is reached. initialization:S = U and T =?Iteration:If S has no unmarked vertex,Stop and report T∪ (X-s) as a minimun cover and M as a maximum matchin

InputSample Output4Translation:Farmer John had just built his new barn last week, and he used the latest milking techniques.Unfortunately, every barn is different because of project issues.In the first week, farmer John casually let the cows into the barn. But the problem is very quickly revealed: every cow is only willing to produce milk in the barn they like. Last week. Farmer John has just gathered information about the cows ' hobbies (which cows are fond of producing milk in each cow). A ba

Title Link: http://acm.hdu.edu.cn/showproblem.php?pid=3605EscapeTime limit:4000/2000 MS (java/others) Memory limit:65536/65536 K (java/others)Total Submission (s): 8001 Accepted Submission (s): 1758Problem Description2012 If This is the end of the world? I don't know how. But now scientists has found that some stars, who can live, but some people does not fit to live some of the planet. Now scientists want your help, was to determine what's all of the people can live in these planets.Inputmore s

F-the King ' s problemTime limit:1000MS Memory Limit:32768KB 64bit IO Format:%i64d %i64 U SubmitStatusPracticeHDU 3861DescriptionThe Kingdom of Silence, the king has a new problem. There is N cities in the kingdom and there is M directional roads between the cities. That means that if there are a road from U to V, and you can only go from the city u to City v, and can ' t go from the City v to the city U. In order to rule he kingdom more effectively, the king want to divide he kingdom into se

could fire down column 2 to destroy T He asteroids at (2,2) and (3,2).SourceUsaco 2005 November Gold1#include 2#include string.h>3 Const intM =510 ;4 BOOLMap[m][m];5 intGirl[m];6 BOOLSta[m];7 intN, M;8 9 BOOLHungary (intx)Ten { One for(inti =1; I ) { A if(Map[x][i] sta[i] = =false) { -Sta[i] =true ; - if(Girl[i] = =0||Hungary (Girl[i])) { theGirl[i] =x; - return true ; - } - } + } - return false ; + } A at intMain () - { -

#include #include#include#include#include#includeusing namespacestd;intn,m,k,ans,cnt,head[1001],vis[1001],match[1001];structuio{intNext,to;} edge[1000001];intAddintXinty) {edge[++cnt].to=y; Edge[cnt].next=Head[x]; HEAD[X]=CNT;}BOOLFindintx) { for(intI=head[x];i;i=Edge[i].next) { inty=edge[i].to; if(!Vis[y]) {Vis[y]=1; if(!match[y]| |find (Match[y])) {Match[y]=x; return true; } } } return false;}intMain () {scanf ("%d%d%d",n,m,k); for(intI=1; i) { intu,v; scanf

For each point on the side of the binary map Dfs, look for all its matching points, if the match point does not match or match the other half can find a new point to match, then the reorganization after the match, otherwise it will not match1 intDfsintk)2 {3 for(intI=head[k];~i;i=Next[i])4 if(!Visit[point[i]]) {5 intp=Point[i];6visit[p]=1;7 if(match[p]==-1||DFS (match[p])) {8match[p]=K;9 return 1;Ten } One } A return 0; - } -

Oil skimmingTime limit:2000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 993 Accepted Submission (s): 422Problem descriptionthanks to a certain "green" resources company, there are a new profitable industry of oil skimming. There is large slicks of crude oil floating in the Gulf of Mexico just waiting to being scooped up by enterprising oil baron S. One such oil baron have a special plane that can skim the surface of the water collecting oil on the water '

Roller coasterTime limit:1000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 12125 Accepted Submission (s): 5302Problem DESCRIPTIONRPG girls today and we go to the amusement park to play, finally can sit on the dream of the roller coaster. However, the roller coaster in each row only two seats, and there is an unwritten rule, is that every girl must find all the boys do partner and her sitting. However, each girl has their own ideas, for example, rabbit only

Outputoutput 2 lines for every case. Output a single number on the first line, which means the number of students who told the truth at most. In the second line, the output of the students who tell the truth, separated by a space. Please note that there is no spaces at the head or tail of each line. If there is more than one, output the list with maximum lexicographic. (in the example above, 1 2 3;1 2 4;1 3 4;2 3 4 is all OK, and 2-3 4 with maximum lexicographic)Sample Input245004 50055005 500

problem 2194 Galaxy collisionAccept:29 submit:102Time limit:30000 mSec Memory limit:327680 KB problem DescriptionIt is predicted that, about 10 billion years later, the Leo Galaxy will collide with the Milky Way galaxy, the collision of two galaxies will merge two galaxies, but no 2 planets will collide with each other. Now some scientists get the result of merging two galaxies, some of the points on the two-dimensional plane, but do not know that the planets belong to the Milky Way, if two plan

Roller coasterTime limit:1000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 12475 Accepted Submission (s): 5446Problem DESCRIPTIONRPG girls today and we go to the amusement park to play, finally can sit on the dream of the roller coaster. However, the roller coaster in each row only two seats, and there is an unwritten rule, is that every girl must find all the boys do partner and her sitting. However, each girl has their own ideas, for example, rabbit only

Test instructions: give you n a positive integer, a pair and a number of primes as a valid number pair. You choose not to exceed the number of k legal pairs, so that you choose the number of the number of related numbers to maximize. Output this value.All 1 can be paired with any 22.Put odd numbers on the left and even on the right.Consider how many "1" are currently being used to dynamically update the maximum match.If K does not exceed the maximum number of matches + the remaining unused 1/2,

∵ can sit on two people per seat, so the maximum match is split.1#include 2#include 3#include 4 using namespacestd;5 #defineN 20016vectorint>G[N2];7typedef vectorint>:: iterator ITER;8 intmat[n2];9 BOOLvis[n2];Ten intn,x,y; One BOOLDfsintU) A { - for(ITER it=g[u].begin (); It!=g[u].end (); it++) - if(!vis[*it]) the { -vis[*it]=1; - if(mat[*it]==-1|| DFS (mat[*it])) - { +mat[*it]=U; - return 1; + } A } at return 0; -

The bare maximum match.1#include 2#include 3#include 4 using namespacestd;5vectorint>g[2002];6typedef vectorint>:: iterator ITER;7 intn,m,mat[2002],x,y;8 BOOLvis[2002];9 BOOLDfsintU)Ten { One for(ITER it=g[u].begin (); It!=g[u].end (); it++) A if(!vis[*it]) - { -vis[*it]=1; the if(mat[*it]==-1|| DFS (mat[*it])) - { -mat[*it]=U; - return 1; + } - } + return 0; A } at intMax_match () - { -memset (mat,-1,sizeof(MAT));int

InputSample Output4Translation:Farmer John had just built his new barn last week, and he used the latest milking techniques. Unfortunately, every barn is different due to engineering problems. The first week, farmer John casually let the cows into the barn, but the problem quickly revealed: Every cow is only willing to milk in the barn they like. Last week, farmer John had just gathered information about the cows ' hobbies (which cows would like to produce milk). A barn can only hold a cow, of