topology for dummies

Topic: Define a semi-connected diagram: Any two points in the graph can be reached in one direction. The maximum half-connected sub-graph of a graph, and the number of the maximum semi-connected sub-graphs of the graph.Idea: Semi-connected graphs are not necessarily without rings. This test instructions me to understand.In fact, the idea of what is not difficult to understand is not difficult to write. In order to ensure the semi-connected, so we must first deal with a diagram of the unicom situ

: application of topological sortInput Line 1th: 3 integers n,m,k,1≤k≤n≤100,000,1≤m≤500,000 Line 2nd: K integer a[i],a[i] means the hacker put 1 viruses on node a[i]. 1≤a[i]≤n 3rd.. M+2 line: 2 integer u,v per line, indicating that there is a network link from node u to node v. The data is guaranteed to be a loop-free diagram. 1≤u,v≤nOutput Line 1th: An integer that represents the total number of viruses in the last network MOD 142857 Sample input 4 4 111 21

Application of embedding a vector Chart into an HTML5 Network Topology When we use HT for Web (HT) to develop HTML5 network topologies and projects with Chart requirements, we feel very painful. The Chart components integrated with HT do not contain coordinates, the presentation is not intuitive, but there is no solution. Let's talk about the specific solution. First of all, the first solution is to add some custom plot areas in comps to define the Ch

Test the remote network topology by monitoring the TTL response Sometimes, the network administrator can configure an internal network to implement communication between a single host and other hosts at different levels. A single Internet Protocol (IP) address may represent many devices that have opened ports on the internal network. Although there are some basic ways to detect them, it is surprising that today's popular tools will also find some rel

sorting It all OutTime limit:1000MS Memory Limit:10000KB 64bit IO Format:%lld %lluDescriptionAn ascending sorted sequence of distinct values are one in which some form of a less-than operator are used to order the Ele ments from smallest to largest. For example, the sorted sequence A, B, C, D implies, a InputInput consists of multiple problem instances. Each instance starts with a line containing-positive integers n and m. The first value indicated the number of objects To sort, where 2 OutputF

Test instructionsGiven N, which represents the N letters starting with a, gives their m-less relation (AIf the first I relationship can be determined in one order of n letters output: Sorted sequence determined after I relations: lined letters. If the first I relationship begins to cause a contradiction, the output is: Inconsistency found after I relations. M relationships can not be determined in the order of output: Sorted sequence cannot be determined.

]=*tmp; Add (*tmp,*it); sum[*it]++; Continue; } if(f[*it]==0sk>0) { Setint>::iterator tmp=it; TMP++; f[*it]=*tmp; //coutAdd (*tmp,*it); sum[*it]++;//coutsk--; Continue; } printf ("%d",*it); Itar=it; Flag=0; Break; } if(flag) {Setint>::iterator itlast=s.end (); itlast--; printf ("%d",*itlast); intx=*Itlast; S.erase (S.begin (), S.find (x)); S.erase (x); for(inttemp=g[x];temp;temp=E[temp].next) {Sum[e[temp].to]--; if(sum[e[temp].t

ZOJ_3795 Grouping (strongly connected component topology) Question:This is my first strongly connected component. Although I have referenced other people's code, it is still very rewarding. The search and processing of strongly connected components is the first step of many graph topics, so it is very important. This is only the processing of Strongly Connected digraphs.Because the relationship between each group of questions is not less than, there i

elements first: #include#include#include#include#include#include#include#includeUsingNamespace Std;#define INT __int64#define INF0x3f3f3f3fConstint MAXN=555;int team[MAXN];int Head[MAXN];int point[MAXN];int NXT[MAXN];int edgecnt;BOOL Vis[MAXN][maxn];int Ingrade[MAXN];voidIni(){Memset(Team,0,sizeof(Team));Memset(Head,-1,sizeof(Head));Memset(Point,-1,sizeof(Point));Memset(NXT,-1,sizeof(NXT));Memset(Vis,0,sizeof(Vis));Memset(Ingrade,0,sizeof(Ingrade)); Edgecnt=0;}voidAdd_edge(int U,Int V){edgecnt+

≤100,000,1≤m≤500,000Line 2nd: K integer a[i],a[i] means the hacker put 1 viruses on node a[i]. 1≤a[i]≤n3rd.. M+2 line: 2 integer u,v per line, indicating that there is a network link from node u to node v. The data is guaranteed to be a loop-free diagram. 1≤u,v≤nOutputLine 1th: An integer that represents the total number of viruses in the last network MOD 142857 Sample input 4 4 111 21 32 33 4 Sample output 6 #include #include#in

Topic Links:http://acm.hdu.edu.cn/showproblem.php?pid=5638Test instructionsGive you a DAG diagram, delete the K-bar, so that you can get a dictionary order as small as possible the topological sortExercisesThe algorithm of topological sorting is changed slightly, if a vertex is less than k, it is added to the priority queue.K reduced after the queue there will be some points do not meet the Code:#include #include#include#include#include#includeusing namespaceStd;typedefLong LongLL;Const intMAXN