caesar cipher encryption

string.Sample InputJSOI07Sample OutputI0o7sjHINTThe length of the data string for 100% does not exceed 100000.Idea: a template title for the suffix array.We just need to copy this string to the back, and then handle the SA, which in turn outputs the starting point in the ranking.#include #include #include #include using namespace STD;#define N n*2-1Const intm=200100;CharCH[M];intn,m=0, Sa[m],t1[m],t2[m],c[m];voidBuild_sa () {intI,p,k,*x=t1,*y=t2; for(i=0; i0; for(i=0; i for(i=1; i1]; for(i=n-1;

given:07jsoi-->07+......+i7jsoi0-->7+......+0I07jso-->i07+......+ojsoi07-->jsoi07+ (7)Oi07js-->oi07+......+sSoi07j-->soi07+jyou can see that 07,7,i07,jsoi07,oi07,soi07 is all the suffixes of the original string, so we only need to sort these suffixes when sorting. This will use the suffix array. Note: Because it is annular, it is necessary to first copy the multiplication string, get the new string, and giveNew StringThe first half of the sequence, and then output each in the multiplication aft

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7:Bzoj 1031: [JSOI2007] character encryption cipher the beginning of the fall array of sa and rank array teacher confused; the topic is to get the order of the last letter Mistaken: The last string after the order is made. Familiarity with rank and SA definitions soon code:1031: #include Bzoj 1031: [JSOI2007] character encryption

http://www.lydsy.com/JudgeOnline/problem.php?id=1031It is easy to think of this as copying the string to its end and then the suffix array out of the SA and output by the interval.Then change the template and put the cardinal sort outside#include Suffix array of the original: #include 　　 DescriptionLike to delve into the problem of JS classmate, and recently fascinated by the encryption method of thinking. One day, he suddenly came up with wha

string over the $sa$ value, the last character of each string corresponds to the $s[sa[i]+n-1]$1#include 2 using namespacestd;3 Chars[200005];4 intsa[200005], wv[2][350005], tong[200005];5 6 BOOLcmpint*tmp,intXintYintj)7 {8 returnTMP[X] = = Tmp[y] tmp[x + j] = = Tmp[y +j];9 }Ten One voidGetsa (intNintm) A { - intp =0, *x = wv[0], *y = wv[1]; - for(inti =0; I i) the++tong[x[i] =S[i]]; - for(inti =1; I i) -Tong[i] + = tong[i-1]; - for(inti = n-1; ~i; --i) +Sa[--tong[x[i

\ (S[sa[i] + n-1] (s=input+input,sa[i]#include #include #include #include #include #include #include using namespaceStd#define N 200001#define REP (I, A, b) for (int i = A; I #define DRP (i, A, b) for (int i = A; I >= b; i--)#define LL Long Longinline intRead () {intx =0, flag =1;Charch = getchar (); while(!isdigit (CH)) {if(! (ch ^'-')) flag =-1; ch = getchar (); } while(IsDigit (ch)) x = (x 1) + (x 3) + CH-' 0 ', ch = getchar ();returnx * FLAG;}intNCharIn[n];intS[n];intSa[n], T1[n], t2[n], c[

evaluated array, and N is Len intI, j, k =0; for(i =1; I i; for(i =0; I k) { for(K. k--:0, j = Sa[ranking[i]-1]; R[i + K] = = R[j + K]; k++); }}intSA[MAXN], R[MAXN];strings;intSTR[MAXN];intMain () {//freopen ("1031.in", "R", stdin); //freopen ("1031.out", "w", stdout); //Cin.sync_with_stdio (false);CIN >>s; intn =s.length (); S= S +s; for(inti =0; I 2; Str[s.length ()]=1; Da (str, SA, s.length ()+1, the); for(inti =0; I ) { if(sa[i]>=n)Continue; intp = Sa[i] + N-1; coutS[p]; } cou

toN-1 DoInc (Wc[wd[i]); $ fori:=1 toM Dowc[i]:=wc[i-1]+Wc[i]; - fori:=n-1 Downto 0 Do - begin the Dec (wc[wd[i]]); -sa[wc[wd[i]]]:=Y[i];Wuyi End; the - fori:=0 toN Doswap (x[i],y[i]); Wu -p:=1; x[sa[0]]:=0; About fori:=1 toN-1 Do $ begin - ifCMP (sa[i-1],SA[I],J) Thenx[sa[i]]:=p-1 - Else beginX[sa[i]]:=p; Inc (P);End; - End; A +j:=j*2; them:=p; - End; $ End; the the the begin theAssign (input,'bzoj1031r.in'); Reset (input); -Assign (output,'Bzoj1031r

Topic: Given a string, the string of the last column after the string is sorted to the beginning of each character.Legend of the suffix array 0.0 last night DC3 did not understand, so wrote a multiplier 0.0 Mr. Luo's 25 lines of code is really abstract Qaq Konjac Konjac Express Understanding can not qaq so I wrote a relatively clear version QaqFirst, this is the ring, so we add the first n-1 character of the string to the end of the string and then the suffix array.After this, enumerate each beg

Portal: http://www.lydsy.com/JudgeOnline/problem.php?id=1031Save the suffix array template.In fact, if the data range is smaller, or the space limit is a little larger, or even as long as the alphabet is a little bit more can use the suffix automaton, but unfortunately the space is not allowed, just use the suffix array!In fact, I still do not understand the code, whether it should be a black box code back down?#include 　　_bzoj1031 [JSOI2007] character encry