(According to the basic principles of Chinese chess) on the double-only handsome board, find all the positions where both sides can fall (the handsome guy cannot meet each other), but only one variable can be used.
Intuitively, we think that we only need to traverse all possible positions of the handsome guy and remove the conflicting positions of the handsome guy. It can be seen that the remaining problem
Electric Research Class-7 Chinese Chess Game Summary
Intelligence: Chinese chess!
In order to enrich the students' after-school life, promote friendship among the students, cultivate their personal interests, and improve their overall quality, we also advocate a good spirit of playing
Problem descriptionChinese chess inside the "will" and "handsome" each stay in their own nine lattice, one step can only move sideways or vertically, and both sides can not meet (can not be in the same vertical line). In the aftermath, some people will use this rule to get out of the wonderful kill trick. Assuming that one party's "will" is a, the other party's "handsome" is B, and now the two sides can appear in all legal positions, the required vari
C + + is the inheritance, it can be the C language of the process of programming, but also the abstract data type of the characteristics of the object-based programming, can be inherited and polymorphic as the characteristics of the object-oriented programming, today to introduce the "C + + Game project: Chinese Chess Development Video Tutorial" Although the project is small, but extremely lean, perfectly f
Cocos2d-X development of Chinese chess 14 game package into APK, 14 apk
In the previous blog, from the return of game scenes to the start scene and the use of xml to display Chinese characters in the game, this blog will be the last article of the Cocos2d-X to develop the Chinese c
The problem of Chinese chess generalsFlyfish 2015-8-11Questions quoted from "The Beauty of programming" Chinese Chess GeneralsGenerals each with only one step, forward, backward, traverse can be, but not out of the "nine", is limited to the 3x3 lattice movement. Will and handsome not in the same straight line directly
Cocos2d-X development of Chinese chess "2" project file overview, cocos2d-x "2"
I 've introduced the function of chess in my previous blog, and I'll show you how to use Cocos2d-X to develop Chinese chess step by step.
Project directory:
Classes: stores public code
Proj
Description
This time, cocoa's problem is related to Chinese chess. On the n-row and M-column checkerboard, you can play a number of guns (which can be 0 ), so that no one can attack another. How many methods can be used to place the attack. It must be clear that in Chinese chess, the way a gun walks is: one gun attack
Chinese chess believe that we are not unfamiliar, but if you want to make Chinese chess through PS, I believe many friends will not. Below, this tutorial will teach you how to make Chinese chess pieces through PS tutorial, togethe
I. Prototype of the topic
Chinese chess friends know that both sides of the "will" and "handsome" far apart, and they can not face. In the game of chess, many masters can use this rule to get out of the exquisite killing. Suppose the board has only "will" and "handsome" two sons (as shown in Figure 1-3) for the following purposes, we agreed to use A for "will", B
This section describes the question of Chinese chess masters.
Code --
Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->
Struct
{Unsigned
Char
A:
4
;Unsigned
Char
B:
4
;} I; For (I. = 1 ; I. 9 ; I. ++ ) For (I. B = 1 ; I. B 9 ; I. B ++ ) If (I. % 3 ! = I. B % 3 )Printf ( " A = % d, B = % d \ n " , I. A, I. B
The question requires that all valid locations of "" (a) and "" (B) be output, and only one byte storage variable can be used;
Solution 1:
1 #includeView code
There are nine methods for a and B, So I = 81, for an integer I = I/9*9 + I % 9; I % 9 with I/9 change round, it is equivalent to a nested loop; an I is used to represent the changes of two values;
Of course, you can also use this method to implement multiple nesting;
Solution 2:
1 #includeView code
Refer to related bit operations
The b
Generate valid methods
Reprinted by the author:
By: 88250
Blog: http:/blog.csdn.net/dl88250
MSN Gmail QQ: DL88250@gmail.com
Method generation is to generate all valid methods, so that computer players can choose the best method in these methods, and finally come out of this. To generate all methods, you can only use the exhaustive method. About 45 Chinese chess methods can be selected at each step. The
Cocos2d-X development of Chinese chess "seven" new board function implementation, cocos2d-x "seven"
In the previous section, I introduced the implementation of the starting function. In this blog, I will introduce the implementation of the new functions.
First, let's take a look.
We can see the Implementation ideas of the new Bureau through the observed implementation results.
1. Hide the selection
Cocos2d-X development of Chinese chess "12" game results display and hide, cocos2d-x "12"
In the previous section, background music is played in the game. This section displays and hides game results.
Let's take a look.
When a player wins, a dialog box indicating that the player wins is displayed.
When the dialog box is clicked, the dialog box and pawns are hidden.
Click Start to change the color of the
The last two methods are clever. One is the bit domain and the other is the remainder.
If unsigned char is not used as the bit field, the size is 4. unsigned char to meet the requirement.
1 void chess1 () {2 struct {3 unsigned char A: 4; 4 unsigned char B: 4; 5} I; 6 cout
The beauty of programming: 1.2 | Chinese chess experts
// Chinese chess handsome question // A, indicates yes, B Indicates handsome //, coordinates of B running position // 1 2 3 // 4 5 6 // 7 8 9 //, the position of B cannot be the same column. // print all solutions that meet the conditions. Public class test {public static void main (string [] ARGs) {for (INT I = 1; I
Output result:
A: 1 B: 2a: 1 B: 3A: 1 B: 5A: 1 B: 6a: 1 B: 8A: 1 B: 9A: 2 B: 1A: 2 B:
Title: http://www.lydsy.com:808/JudgeOnline/problem.php?id=1801Analysis:Only 50 of the state compression ...and then we searched the puzzle and found it was DP.First, it's easy to get up to 2 pieces per row.F[i][j][k] means that there are J columns in the front I row, 1 pieces are put in the K column, 2 pieces are placed in the column, then there are m-j-k.Then consider the relationship between the position of the pawn in line I and the state of the former i-1 line:1. If I do not put a pawn: f[i
Results s->setvisible (false); Set the pawn to the initial position S->setposition (CCP (WINSIZE.WIDTH/2, Winsize.height)); Visible = false; Change the color of the player's pawn _redside =! _redside; Set red to go first _redtrun = true; Re-get a new inning (obj);In the Scenegame member function void Scenegame::movecomplete (ccnode* movetone, void* _killid) Add the following code to implement when the red handsome or black will be killed, the game Resu
The beauty of programming: Chinese chess mastersI. Differences between interview questions and acm questions.
I have been reading interview questions over the past few days, and I feel different from my previous questions on acm. In terms of subject matter, acm generally chooses generic algorithms that seldom involve local APIs and other things due to different client systems. At the same time, acm seldom l
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