m17 r3

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CCNP comprehensive experiment-

CCNP comprehensive experiment- The top labs are as follows: 650) this. width = 650; "alt =" "border =" 0 "src =" http://img1.51cto.com/attachment/201104/185551130.jpg "/>Lab requirements: 1: R3, R4 for NAT, R3 E0/1 for export, and R4 E0/0 for export. 2: R3, R4, R5, R7, R8 do OSPF, R3, R4, R5, R7 do frame-relay, R7 do

Study notes (third week)

-circuit after the current of I1 ';Resistance R2 short-circuit process: short-circuit before the current is I2, torque is Tm2, the speed of N2, short-circuit after the current of I2 ';The short circuit of the Resistance R3: The current is i3 before the short circuit, the torque is Tm3, the speed is N3, the current after the short circuit is i3 '.R1 before short Circuit:Tm1-tl=j (DN1/DT) (2PI/60)Tm1=kt*i1U=KE*N1+I1 (R+R1+R2+

Multi-region ospf and virtual connections, and Remote Areas

0, R2 and R3 belong to the ospf region 1, R3 and R4 belong to the ospf Region 2, and R2 and R5 adopt the rip Protocol; 2. use virtual connection to connect area2 and area0 through area1. 3. route table reduction is achieved by setting a remote route and a full remote route. 4. achieve network-wide interconnection. Note: device models: R1, R2, R3: R2661; R4, R5:

Basic knowledge of the operating process of UCOS on S3C2410 (2)-C language and stack.

* argv []) { Int A = 3, B = 5; Max (A, B ); Return 0; } Int max (int x, int y) { If (x> Y) Return X; Else Return y } The function is very simple. In the main function, call an external function max to use the number with a large value in two numbers and return the result. The following describes how Arm Assembly implements these functions and how to use the intermediate stack. . File "Max. c" . Text . Align 2 . Global main . Type main, % Function Main: @ ARGs = 0, pretend = 0, frame = 16 @ Fram

Process deadlock Terminator-Bankers Algorithm

next resource requested by the other party The most representative way to avoid deadlocks is the bankers algorithm. As for what the Banker algorithm is, I will not go into details here. To be honest, it is difficult to understand the concept alone, or to explain the example to understand what the Banker algorithm is. Example: Suppose there are three types of mutex resources: R1, R2, and R3. The available resources are 9, 8, and 5. at the time of T0

OSPF interconnection in broadcast mode on NBMA Network

In this experiment, OSPF in broadcast mode is deployed on the NBMA network. The network topology is partially interconnected. R1 Configuration: Interface Loopback1 Ip address 1.1.1.1 255.255.255.0 ! Interface Loopback2 Ip address 1.1.2.1 255.255.255.0 ! Interface Serial1/0 Ip address 10.0.1.1 255.255.255.0 Encapsulation frame-relay Ip ospf network broadcast ! Router ospf 1 Router-id 1.1.1.1 Log-adjacency-changes Network 1.1.1.0 0.0.0.255 area 0 Network 1.1.2.0 0.0.0.255 are

EIGRP Basic Experiment 1

) #login % login disabled on line 0, until ' password ' is set R2 (Config-lin e) #password 11223344 R2 (config-line) #no exec-timeout R2 (config-line) #logging synchronous R2 (config-line) #end r2#conf T Enter The configuration commands, one per line. end with cntl/z. R2 (config) #int s0/0 R2 ( CONFIG-IF) #ip address 12.1.1.2 255.255.255.0 R2 (config-if) #no shu R2 (config-if) #int lo 0 R2 (config-if) #ip Address 2.2.2.2 255.255.255.0 R2 (config-if) #end r2#conf t Enter configurati

Linux kernel Boot

supports the current CPU, __lookup_machine_type detect whether the current board is supported, and __create_ Page_tables Create page table, __enable_mmu enable MMU. If no support is found after a series of self-test procedures, skip to __error_p or __error_a. Here we first open the __lookup_machine_type. . Type __lookup_machine_type,%function__lookup_machine_type: ADR R3, 3b Ldmia R3, {r4

Dual-point bidirectional re-release control

Lab requirements and application environment:1. Execute two-way re-release on R5, and then execute two-way re-release on R32. analyze the causes and solutions of the second-tier route3. How can I achieve Load Balancing when R4 is required to go to 1.1.1.1?4. Ask R4 to go to the next hop of 11.11.11.11 first R3 and R5 for backup. How can this problem be solved? Experiment debugging process:R1 Configuration:Router rip // configure RIPVersion 2Passive-i

CCNA lab review 3, rip

Dynamic Route RIP RIP broadcasts UDP packets to exchange route information and sends route information updates every 30 seconds. The maximum number of hops supported by RIP is 15. The experiment has been verified, but the topology is borrowed. Tutorial topology: 650) this. width = 650; "src =" http://www.bkjia.com/uploads/allimg/131227/04533355B-0.png "title =" dsfds.png "/> 1. IP Address Table: PC1 ip: 192.168.10.2/24 Gateway: 192.168.10.1 PC2 ip: 192.168.40.2/24 Gateway: 192.168.30.1 R1 F0/019

Dynamic routing 2--Distance vectors

, 192.168.2.0 I have a hop count of 0 (direct connection), If the route from R2 gets 192.168.2.0 is 1 (more than one router R2 through R2 to the network 192.168.2.0), R1 chooses not to update the routing information to the network 192.168.2.0/24; for network 192.168.3.0/ 24,R1 check its own routing table found that there is no such routing information, so choose to update the routing information to 192.168.3.0/24, and to the network 192.168.3.0/24 need to go through the router R2 (the next hop t

Ubuntu 16.04 Tomcat Installation

Installing Tomcat in two steps: JDK and TomcatInstalling the JDK1. Download JDK on ORALCE website2. Unzip and create the JDK directory~# Tar jdk-89121-linux-x64.tar.gz~# MKDIR/USR/LIB/JVM~# Cp-r JDK1.8.0_121/USR/LIB/JVM3. Add Environment variablesRestart after adding the following at the end of/ETC/BASH.BASHRCExport java_home=/usr/lib/jvm/jdk1.8.0_121Export JRE_HOME=${JAVA_HOME}/JREExport Classpath=.:${java_home}/lib:${jre_home}/libExport Path=${java_home}/bin: $PATH4. Test the JDK~# java-versio

MongoDB Learning Note Series One

replica set: Refer to the MONGO replica set installation script. Sh VIII, Shard shard configuration1, start two MONGO servers mkdir-p/home/m17/home/m18/home/m20/home/m30/home/Mlog Mongd--dbpath/home/m17--logpath/home/mlog/m17.log--fork--port 27017 mongd--dbpath/home/m18--logpath/home/mlog/m 18.log--fork--port 27018 2, configure Configserver, manage meta informat

ACL comprehensive experiment

-line) # loginRouter (config-line) # hostname RX // (commands for the four routers are R1, R2, R3, and R4 respectively) 2. configure the interface address. This is not much to say. Let's take R3 as an example R3 (config )#R3 (config) # int f1/1R3 (config-if) # ip address 192.168.13.3 255.255.255.0R3 (config-if) # no sh

Static Routing can also be used for communication between multiple network segments

)#hostnameR2 R2(config)# R2(config)#interfaceFastEthernet0/1 R2(config-if)#ipaddress112.237.228.1255.255.255.0 R2(config-if)#noshutdown %LINK-5-CHANGED:InterfaceFastEthernet0/1,changedstatetoup R2(config-if)# R2(config-if)#exit R2(config)#interfaceFastEthernet0/0 R2(config-if)#ipaddress192.168.10.2255.255.255.0 R2(config-if)#noshutdown %LINK-5-CHANGED:InterfaceFastEthernet0/0,changedstatetoup R2(config-if)#end R2#conft Enterconfigurationcommands,oneperline

Some new imagefeature

1. Stub Prevent the router from sending unnecessary queries. When a router is set to stub, other routers will not send queries to it. You can set the advertised routes (connected, redistributed, static, summary, or receive-only) 2. Stub leaking--- + ---------------- + ---- R1 r2 | E0/0 | R3---------------R4 E0/1 | --- + ---- 192.168.1.0 R1, r2 declares the default route to R3 and R4.

Virtual short "" virtual broken "two axes, deal with 11 operational amplifiers details

current flowing through R2. Current I1 = (Vi-v-)/R1…… flowing through r1 ...... Current of a flowing through R2 I2 = (V-Vout)/R2 ...... B V-= V + = 0 ...... C I1 = I2 ...... D. Solve the above junior high school algebra equation vout = (-R2/R1) * VI. This is the input and output relationship of the legendary reverse amplifier. Figure 2 VI and V-virtual short, Vi = V -...... A. Due to virtual disconnection, there is no current input and output at the reverse input en

A detailed explanation of the Equals and Hashcode methods in Java set--java _java

, so first compare the hashcode value, r1 and R2 object X, Y attribute values are unequal, so their hashcode are different, so the R2 object can be put in, but the X,y attribute value of the R3 object is the same as that of the R1 object, so the hashcode is equal, at which point the Equals method of R1 and R3 is compared, because of his two x, The Y value is equal, so the R1,

Equals and hashcode deep understanding and hash algorithm principle __ algorithm

; } We've rewritten the hashcode and Equals methods in the parent object, and see the Hashcode and Equals methods, if the x,y values of two Rectobject objects are equal, their hashcode values are equal, At the same time equals returns true; Here is the test code: Package Com.weijia.demo; Import Java.util.HashSet; public class Demo {public static void Main (string[] args) { hashset We deposited four objects into the hashset, printing the size of the set collection,

Installation and configuration of the latest version of Redis Linux system

Tags: code install settings boot span com repr installation test1.redis DownloadsWebsite address: Https://redis.io/downloadBaidu Cloud Address: Link: Http://pan.baidu.com/s/1c1Hu2gK Password: h17z2. Unzip[root@MiWiFi-R3-srv local]# tar -zxvf ~/redis-4.0.2.tar.gz -C . 1 3. Installation[Root@MiWiFi-r3-srvLocal# yum install-y gcc-c++[root @MiWiFi-r3-sr

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