* 1012. digital classification

1/* 2 * Main. C 3*1012. digital classification 4 * created on: August 30, 2014 5 * Author: boomkeeper 6 ********* part through ******* 7 */8 9 # include <stdio. h> 10 # include <math. h> 11 12 Void A1 (INT in, int * sum) {13 14 if (in % 5 = 0 & in % 2 = 0) 15 (* sum) + = In; 16} 17 18 void A2 (INT in, int * sum, int * count) {19 20 if (in % 5 = 1) {21 (* sum) + = POW (-1, * count) * in; 22 (* count) ++; 23} 24} 25 26 void A3 (INT in, int * count) {27 28 If (in % 5 = 2) 29 (* count) ++; 30} 31 32 void A4 (INT in, int * sum, int * count) {33 34 if (in % 5 = 3) {35 (* count) ++; 36 (* sum) + = in; 37} 38} 39 40 void A5 (INT in, int * max) {41 42 if (in % 5 = 4) 43 If (* max <in) 44 * max = In; 45} 46 47 void output (int * sum1, int * sum2, int * count3, int * sum4, int * count4, int * max) {48 if (* sum1 = 0) 49 printf ("N"); 50 else51 printf ("% d", * sum1 ); 52 53/* the result of the staggered sum may be 0, and the output N or 0 is to be determined */54 if (* sum2 = 0) 55 printf ("N "); 56 else57 printf ("% d", * sum2); 58 59 If (* count3 = 0) 60 printf ("N"); 61 else62 printf ("% d ", * count3); 63 64 if (* count4 = 0) 65 printf ("N"); 66 else67 printf ("%. 1f ", (float) (* sum4)/(* count4); 68 69 If (* max = 0) 70 printf (" N "); 71 else72 printf ("% d \ n", * max); 73} 74 75 int main (void) {76 77 int in; 78 int N; // N79 int I; 80 int sum1 = 0, sum2 = 0, sum4 = 0; // sum81 int count2 = 0, count3 = 0 in A1, A2, and A4, count4 = 0; // count 82 int max = 0 in A2, A3, and A4; // The maximum number of records in A5 is 83 84 scanf ("% d", & N ); 85 86 for (I = 0; I <n; I ++) {87 scanf ("% d", & in); 88 A1 (in, & sum1 ); 89 A2 (in, & sum2, & count2); 90 A3 (in, & count3); 91 A4 (in, & sum4, & count4); 92 A5 (in, & MAX); 93} 94 95 output (& sum1, & sum2, & count3, & sum4, & count4, & MAX); 96 97 return 0; 98}

 

This question took a long time. I didn't submit it at the time. I couldn't think of the idea at the time. I 'd like to release it first, or I will forget it later.

 

Question link:

Http://pat.zju.edu.cn/contests/pat-b-practise/1012

 

 

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* 1012. digital classification