1493: [NOI2007] Necklace Factory

Source: Internet
Author: User

Segment tree.

Really is a line tree.

With the exception of operations, the line tree is easy to handle, and the problem is how to handle operations 1 and 2. (This is not expected).

We use a Delta maintenance Operation 1, +k if there is no rotation, or-K.

Each time I and J are read into the process with trans, the success in the O (1) time resolved the operation 1 and 2.

Details are important.

#include <cstdio>#include<algorithm>#include<cstring>using namespacestd;Const intMAXN =2000000+Ten;structNode {intlc,rc,cnt; };structSegtree {#defineLC (x) ((x) <<1)#defineRC (x) (((x) <<1) |intL[MAXN],R[MAXN],TAG[MAXN];    Node A[MAXN]; intrev,delta,n,tmp; voidTransint&x,int&y) {if(rev) {//Reverse RotationX= (n-x+2-delta+n)%N; Y= (n-y+2-delta+n)%N;        Swap (x, y); }        Else{//Positive Spinx= (x-delta+n)%N; Y= (y-delta+n)%N; } x=x?x:n; Y=y?y:n; }        voidPushintx) {if(!tag[x])return; A[LC (x)].lc=A[RC (x)].lc=Tag[x]; A[LC (x)].rc=A[RC (x)].rc=Tag[x]; TAG[LC (x)]=TAG[RC (x)]=Tag[x]; A[LC (x)].cnt=A[RC (x)].cnt=1; TAG[X]=0;        } Node Update (node A,node b) {node res; RES.LC=a.lc; Res.rc=b.rc; Res.cnt=a.cnt+b.cnt-(a.rc==b.lc); returnRes; }        voidUpdateintx) {a[x]=Update (A[LC (x)],A[RC (x)]); }        voidBuildintXintLintR) {l[x]=l; r[x]=s; if(l==R) {scanf ("%d",&tmp); A[X].LC=a[x].rc=tmp; A[x].cnt=1; return; }        intMid= (l+r) >>1;        Build (LC (x), l,mid); Build (RC (x), Mid+1, R);    Update (x); }        voidColorintXintLintRintv) {if(L>r[x] | | R&LT;L[X])return; if(L<=l[x] && r[x]<=R) {tag[x]=v; A[X].LC=a[x].rc=v; A[x].cnt=1; return;        } push (x);        Color (LC (x), l,r,v);        Color (RC (x), l,r,v);    Update (x); } Node Query (intXintLintR) {if(L<=l[x] && r[x]<=r)returnA[x]; intMid= (L[x]+r[x]) >>1;        push (x); if(R<=mid)returnQuery (LC (x), l,r); Else if(L>mid)returnQuery (RC (x), l,r); Else returnUpdate (query (LC (x), l,r), query (RC (x), l,r)); }        voidPawsintIintj) {trans (i,j); Node cur;intCI,CJ; if(i<=j) {cur=query (1, i,j); CI=CUR.LC; cj=cur.rc; }        Else{cur=query (1, J,i); CJ=CUR.LC; Ci=cur.rc; } Color (1, I,I,CJ); Color (1, J,J,CI); }        voidrotate () {intK; scanf ("%d",&k); if(rev) Delta= (Delta-k+n)%n;//Reverse Rotation        ElseDelta= (delta+k)%n;//Positive Spin    }        voidPaintintIintJintv) {trans (i,j); if(i<=j) Color (1, i,j,v); Else{color (1, i,n,v); Color (1,1, j,v); }    }        voidC1 () {Node cur; Cur=query (1,1, N); printf ("%d\n", Max (cur.cnt-(cur.lc==cur.rc),1)); }        voidC2 (intIintj) {trans (i,j);        Node cur; if(I&LT;=J) Cur=query (1, i,j); ElseCur=update (Query (1, i,n), query (1,1, J)); printf ("%d\n", cur.cnt); }        voidinit () {intC; scanf ("%d%d",&n,&c); Rev=delta=0; Build (1,1, N); }}seg;Charop[ -];intk,i,j,x,q;intMain () {seg.init (); scanf ("%d",&q);  while(q--) {scanf ("%s", op); if(op[0]=='R') seg.rotate (); Else if(op[0]=='F') seg.rev^=1; Else if(op[0]=='S') {scanf ("%d%d",&i,&j);        Seg.paws (I,J); }        Else if(op[0]=='P') {scanf ("%d%d%d",&i,&j,&x);        Seg.paint (I,J,X); }        Else if(op[0]=='C'&& op[1]=='S') {scanf ("%d%d",&i,&j);        SEG.C2 (I,J); }        Elseseg.c1 (); }    return 0;}

1493: [NOI2007] Necklace Factory

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