5-35 mean value of rational number (20 points)

A program is required to calculate the average of n rational numbers.

Input format:

Enter the first line to give the positive integer n (≤100), the second line in a1/b1 a2/b2 … the format given n fractional form of the rational number, where the numerator and denominator are all integers in the shaping range, if negative, the negative sign must appear at the front.

Output format:

The a/b average of n rational numbers is output in the format of a row. Note must be the simplest fractional form of the rational number, and if the denominator is 1, only the molecules are output.

Input Sample 1:

41/2 1/6 3/6 -5/10

Output Example 1:

1/6

Input Sample 2:

24/3 2/3

Output Example 2:

1

#include <iostream>using namespace std; #define N 100struct rational{int N;  int D;}; int gcd (int a, int b) {int temp;if (a = = 0 & b = = 0) {return 0;} if (a = = 0) {return b;} if (b = = 0) {return A;} while (1) {temp = a%b;if (temp = = 0) {return b;} A = B;b = temp;} return b;} int main (void) {struct Rational ra[n],r;int n;cin>>n;for (int i = 0; i < N; i++) {scanf ("%d/%d", &RA[I].N, & ; ra[i].d);} R.N = 0;R.D = 1;for (int i = 0; i < n; i++) {R.N = r.n*ra[i].d + R.D*RA[I].N;R.D = r.d*ra[i].d;} R.D *= N;  Average int g = gcd (R.N, R.D); if (g! = 0) {R.N/= g;r.d/= G;} if (R.D = = 1) {cout << R.N;} else if (R.N = = 0) {cout << R.N;} Else{cout << R.N << '/' << R.D;} return 0;}

　　

5-35 mean value of rational number (20 points)