8String to Integer (atoi)

8 String to Integer (atoi)

Links: https://leetcode.com/problems/string-to-integer-atoi/
Problem Description:
Implement atoi to convert a string to an integer.

Hint:carefully consider all possible input cases. If you want a challenge, please don't see below and ask yourself what is the possible input cases.

Notes:it is intended-problem to be specified vaguely (ie, no given input specs). You is responsible to gather all the input requirements up front.

Update (2015-02-10):
The signature of the C + + function had been updated. If you still see your function signature accepts a const char * argument, please click the reload button to reset your cod E definition.

Spoilers alert ... click to show requirements for atoi.

Requirements for Atoi:
The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, the starting from this character, takes a optional initial plus or minus sign followed by as many numerical digits as P Ossible, and interprets them as a numerical value.

The string can contain additional characters after those that form the integral number, which is ignored and has no Effe CT on the behavior of this function.

If the first sequence of non-whitespace characters in STR isn't a valid integral number, or if no such sequence exists be Cause either str is empty or it contains only whitespace characters, no conversion is performed.

If No valid conversion could be performed, a zero value is returned. If the correct value is out of the range of representable values, Int_max (2147483647) or int_min ( -2147483648) is Returne D.

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To convert a string to int, be aware that:
1 The space at the beginning of the string needs to be removed;
2 The string begins with a symbol (' + ', '-'), must start with a number, otherwise return 0;
3 in the process of conversion, if a non-numeric situation occurs, the conversion terminates immediately;
4 Note the problem of overflow, if the number is greater than Int_max returns INT_MAX, if less than Int_min returns Int_min.

Class Solution {Public:int myatoi (string str) {if (str== "") return 0;        Str=str.substr (Str.find_first_not_of (""));        BOOL Flag=true; for (int i=0;i<str.size (); i++) {if (str[i]-' 0 ' <10&&str[i]-' 0 ' >-1) {if (i            &GT;1) return 0;                else if (i==1) {if (str[0]== '-') flag= false;                else if (str[0]!= ' + ') return 0;                STR=STR.SUBSTR (1);            Break         } break;        }} long long int result=0;             for (int i=0;i<str.length (); i++) {if (str[i]-' 0 ' <10&&str[i]-' 0 ' >-1) {                result=result*10+str[i]-' 0 ';                   if (Result>int_max) {if (!flag) return int_min;                          else return Int_max; }            } else break;        } if (!flag) Result=-result;    return result; }};

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8String to Integer (atoi)