Analysis of Pat computer questions from Zhejiang University 1009. Product of polynomials (25)

1009. Product of polynomials (25) Time Limit 400 MS
The memory limit is 32000 kb.
Code length limit: 16000 B
Criterion author Chen, Yue

This time, you are supposed to find a * B where A and B are two polynomials.

Input specification:

Each input file contains one test case. each case occupies 2 lines, and each line contains the information of a polynomial: K N1 an1 N2 an2... NK ank, where k is the number of nonzero terms in
The polynomial, Ni and Ani (I = 1, 2 ,..., k) are the exponents and coefficients, respectively. it is given that 1 <= k <= 10, 0 <= NK <... <N1 <= 1000.

Output specification:

For each test case you shoshould output the product of A and B in one line, with the same format as the input. notice that there must be no extra space at the end of each line. please be accurate up to 1 decimal place.

Sample Input

2 1 2.4 0 3.22 2 1.5 1 0.5

Sample output

3 3 3.6 2 6.0 1 1.6

# Include <iostream> # include <vector> # include <algorithm> # include <iomanip> using namespace STD; typedef struct node {int exp; // index float COE; // coefficient} node; node product (node A, Node B) {. exp =. exp + B. exp;. COE =. COE * B. COE; return a;} bool compare (node A, Node B) {return. exp> B. exp;} int main () {node; int M, N; vector <node> vec1, vec2, VEC, vec3; vector <node >:: iterator it1, it2; cin> m; while (M --) {CIN> Node. exp> node. COE; vec1.push _ back (node);} CIN> N; while (n --) {CIN> node. exp> node. COE; vec2.push _ back (node);} For (it1 = vec1.begin (); it1! = Vec1.end (); it1 ++) for (it2 = vec2.begin (); it2! = Vec2.end (); it2 ++) {node T = product (* it1, * it2); If (T. COE! = 0) Vec. push_back (t);} Sort (VEC. Begin (), VEC. End (), compare); For (it1 = Vec. Begin (); it1! = Vec. End (); it1 = it2) {for (it2 = it1 + 1; it2! = Vec. end () & (* it1 ). exp = (* it2 ). exp); it2 ++) (* it1 ). COE + = (* it2 ). COE; If (* it1 ). COE! = 0) {vec3.push _ back (* it1) ;}} cout <vec3.size (); For (it1 = vec3.begin (); it1! = Vec3.end (); it1 ++) cout <"" <(* it1 ). exp <"" <fixed <setprecision (1) <(* it1 ). COE; cout <Endl; // system ("pause"); Return 0 ;}