Analysis of the latest GMAT mathematical mechanism in August

Consult QQ: 83735073

1. A total of 4000 fish, 1/4 of which are marked at least once, and 400 are marked at least twice. Ask the probability that a fish is caught at random from the fish.

1000 fish marked> = 400 fish marked at a time> = twice

So only 600 are marked once

600/4000 = 15%

2. A basketball team played 10 games with an average of 12 goals. Can a team score more than 40 in a single game?

Condition 1: a total of 55 goals were scored in the first five matches;

Condition 2: no less than 9 entries can be entered each time.

Question 1 scored 120 goals

Separate condition 1:

55 in the first five games, 41 in 6th, and 24 in the last four games,

Of course, there may be more than 40 goals in a game, which is correct;

Separate condition 2:

If there are no fewer than 9 goals each game, at least 9 goals are required. If you want to score as many goals as possible in a certain game, we can set at least the number of other matches. Assume that 9 of the 9 matches in 10 matches are all 9, so if we have scored 81 in a single game, we can only enter 39 in a single game, and we cannot have more than 40. Therefore, the single condition 2 is sufficient (that is, it is impossible to have more than 40 records)

Answer: d

3. A total of 2400 people in a region,

In the statistical data of March, the proportion of the unemployed population is 6%;

In the statistical data for March, the proportion of non-working population is 3%.

Ask how many people did not have a job in March. Assume that there are only 100 people, 6 were not working in November, and 3 were not working in December.

It indicates that three of the six people who did not work in November found a job in the next month. The three were "those who had a job in December did not have a job in November ", that is to say, this proportion accounts for 3%

Corresponding to 2400 persons, then 72 persons

Answer: 72

The understanding of a dog owner is to consider two extreme situations. ** people who did not work in December (3%), including those who did not work in November (6%) in 3%, December of the employees had jobs but did not work in November. ** in December, none of the employees did not work in November. In 6%, December of the employees did not work in November, the answer range is 72 ~ 144

4. V1: A person has 25, 10, and 5 coins. The number of 25-cent coins is twice the number of 10-cent coins, and the number of 10-cent coins is twice the number of 5-cent coins. Q: How many times the value of a 25 cent coin is the value of a 5 cent coin. (The description should be clear. Do not make a mistake in the relationship between "coins" and "value)

V2: 10 cents is twice the number of 5 cents and 25 cents is twice the number of 10 cents. Question 25: total value and 5 total value

(Key: has twice as... as counter, combined value, remember to multiply the number by the unit value)

V1 is used to calculate a multiple relationship, so we can find the simplest number to substitute,

According to the question, if the numbers are, 2, and 1, the corresponding values are, 20, and 5, respectively,

The value of 25 points is 20 times the value of 5 points.

Answer: 20x

The idea of V2 is the same as that of V1, but this is not a multiple relationship, but a total value. How can we find it without a specific number? The question information should be incomplete.

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