Title: Given a tree, select some points in a subtrees tree, salary and not exceed m, the number of points * The maximum of leadership capacity of a sub-root node
Consider for each node, we maintain a data structure in which greed seeks employment with small salaries.
Every single node violence reconstruction must not be possible. We consider the available data structures. Each node merges the information of the child nodes directly to
A treap that can be combined with a revelation. can also be used to stack
Today deliberately to learn this play should be 0.0 first wrote the left-leaning tree and then wrote the next random heap ... The latter is much faster than just suggesting that you start with a left-leaning tree.
In a word, the balance tree constant is all about 0.0.
Treap+-inspired merger
#include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #define M 100100using namespace Std;typedef Long long ll;struct abcd{abcd *ls,*rs;int key;int cnt,siz;ll num,sum;abcd (ll X,int y); v OID maintain ();} *null=new ABCD (0,0), *tree[m];struct edge{int To,next;} Table[m];int head[m],tot;int n,root;ll m,ans,leadership[m];void Add (int x,int y) {table[++tot].to=y;table[tot].next= Head[x];head[x]=tot;} ABCD:: ABCD (ll X,int y) {ls=rs=null;sum=x*y;num=x;cnt=siz=y;key=y?rand (): 0;} void ABCD:: Maintain () {siz=ls->siz+rs->siz+cnt;sum=ls->sum+rs->sum+num*cnt;} void Zig (ABCD *&x) {ABCD *y=x->ls;x->ls=y->rs;y->rs=x;x=y;x->rs->maintain ();} void Zag (ABCD *&x) {ABCD *y=x->rs;x->rs=y->ls;y->ls=x;x=y;x->ls->maintain ();} void Insert (ABCD *&x,ll y,int z) {if (x==null) {x=new abcd (y,z); return;} if (y==x->num) X->cnt+=z;else if (y<x->num) {Insert (x->ls,y,z), if (X->ls->key>x->key) Zig ( x);} Else{insert (x->RS,Y,Z); if (X->rs->key>x->key) Zag (x);} X->maintain ();} int query (ABCD *x,ll y) {if (x==null) return 0;ll temp=x->ls->sum;int re=0;if (y<=temp) return Query (x->ls,y); Re+=x->ls->siz;y-=temp;if (y<=x->num*x->cnt) return re+y/x->num;re+=x->cnt;y-=x->num*x- >cnt;return re+query (x->rs,y);} void decomposition (abcd *&x,int y) {if (x==null) return;D ecomposition (x->ls,y);D ecomposition (x->rs,y); Nsert (tree[y],x->num,x->cnt);d elete X;x=null;} void tree_dp (int x) {int i;for (i=head[x];i;i=table[i].next) {TREE_DP (table[i].to); if (tree[x]->siz<tree[table[ I].to]->siz) Swap (tree[x],tree[table[i].to]);D ecomposition (tree[table[i].to],x);} Ans=max (Ans,leadership[x]*query (Tree[x],m));} int main () {//freopen ("2809.in", "R", stdin),//freopen ("2809.out", "w", stdout); int I,fa;ll x;cin>>n>>m; for (i=1;i<=n;i++) {scanf ("%d%lld%lld", &fa,&x,&leadership[i]), if (!FA) Root=i;else Add (fa,i); Tree[i] =new ABCD (x,1);} TREE_DP (root); cout<<aNs<<endl;} lld!!
Left-leaning tree
#include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #define M 100100using namespace Std;struct abcd{abcd *ls,*rs;int num,h;abcd (int x);} *null=new ABCD (0), *tree[m];struct edge{int To,next;} Table[m];int head[m],tot;int N,m,root,leadership[m],sum[m],size[m];long long ans;void Add (int x,int y) {Table[++tot]. To=y;table[tot].next=head[x];head[x]=tot;} ABCD:: ABCD (int x) {ls=rs=null;num=x;if (x) H=0;else h=-1;} abcd* Merge (ABCD *x,abcd *y) {if (x==null) return y;if (Y==null) return x;if (x->num<y->num) swap (x, y); x->rs= Merge (X->rs,y), if (x->ls->h<x->rs->h) swap (X->LS,X->RS); X->h=x->rs->h+1;return x ;} void tree_dp (int x) {int i;for (i=head[x];i;i=table[i].next) {TREE_DP (table[i].to); Tree[x]=merge (tree[x],tree[table[ I].to]); Sum[x]+=sum[table[i].to];size[x]+=size[table[i].to];while (sum[x]>m) {sum[x]-=tree[x]->num;--size[ X];tree[x]=merge (Tree[x]->ls,tree[x]->rs);}} Ans=max (ans, (long Long) size[x]*leadership[x]);} IntMain () {int i,fa,x;cin>>n>>m;for (i=1;i<=n;i++) {scanf ("%d%d%d", &fa,&x,&leadership[i]); if (!FA) Root=i;else Add (fa,i); tree[i]=new abcd (x); sum[i]=x;size[i]=1;} TREE_DP (root); Cout<<ans<<endl;}
Random Heap
#include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #define M 100100using namespace Std;struct abcd{abcd *ls,*rs;int num;abcd (int x);} *null=new ABCD (0), *tree[m];struct edge{int To,next;} Table[m];bool son;int head[m],tot;int N,m,root,leadership[m],sum[m],size[m];long long ans;void Add (int x,int y) {table[ ++tot].to=y;table[tot].next=head[x];head[x]=tot;} ABCD:: ABCD (int x) {ls=rs=null;num=x;} abcd* Merge (ABCD *x,abcd *y) {if (x==null) return y;if (Y==null) return x;if (x->num<y->num) swap (x, y); if (son^=1) X->rs=merge (x->rs,y); Elsex->ls=merge (x->ls,y); return x;} void tree_dp (int x) {int i;for (i=head[x];i;i=table[i].next) {TREE_DP (table[i].to); Tree[x]=merge (tree[x],tree[table[ I].to]); Sum[x]+=sum[table[i].to];size[x]+=size[table[i].to];while (sum[x]>m) {sum[x]-=tree[x]->num;--size[ X];tree[x]=merge (Tree[x]->ls,tree[x]->rs);}} Ans=max (ans, (long Long) size[x]*leadership[x]);} int main () {int i,fa,x;cin>>n>>m;for (i=1;i<=n;i+ +) {scanf ("%d%d%d", &fa,&x,&leadership[i]), if (!FA) Root=i;else Add (fa,i); tree[i]=new abcd (x); sum[i]=x; Size[i]=1;} TREE_DP (root); Cout<<ans<<endl;}
Bzoj 2809 APIO2012 dispatching treap+ Apocalypse merge/Can-heap