Cannot use = = to determine two floating-point numbers equal

When judging whether the two floating-point numbers A and B are equal, do not use a==b, you should determine the absolute value of the difference between the two
Fabs (A-B) is less than a threshold value, such as 1e-9.

////When judging whether the two floating-point numbers A and B are equal, do not use a==b, you should determine the absolute value of the difference between the two////fabs (A-B) is less than a threshold value, such as 1e-9. //#include <stdio.h>//#include <math.h>//#define EPSILON 0.000001//int main ()//{//float i;//    //dead Loop//    //For (i = 0; i = ten; i + = 0.4)//    //{//    //printf ("%.11f\n", I);//    //}//    //stop near the 10//For (i = 0;!) (Fabs (I-10) < EPSILON); i + = 0.4)//    {//printf ("%.11f\n", I);//    }////printf ("%.11f\n", I);////return 0;//}#include<stdio.h>#include<math.h>#defineEPSILON 1e-6//Program output://A + b! = 0.7//FA + fb = = 0.7//Please press any key to continue ...intMain () {floatA =0.3; floatb =0.4; floatc = A +b; if(c = =0.7) printf ("A + b = = 0.7\n"); Elseprintf ("A + b! = 0.7\n"); floatFA =0.3; floatFB =0.4; floatFC = FA +FB; if(Fabs (FC-0.7) <EPSILON) printf ("FA + fb = = 0.7\n"); Elseprintf ("FA + fb! = 0.7\n"); return 0;}

As can be seen from the program, because the IEEE floating-point standard indicates that data precision is limited, floating-point operations can easily cause small errors, so you cannot use the equal sign to determine whether the floating-point numbers are equal.

Cannot use = = to determine two floating-point numbers equal