Capture the essence of Ruby Regular Expression usage

Speaking of Ruby, of course, we need to mention its regular expression mechanism. As a powerful matching language, regular expressions are increasingly used in different fields, from string verification, matching, to web page extraction. Although some people criticize the matching efficiency with regular expressions, it does not matter considering the strong matching ability of regular expressions.

When talking about Ruby regular expressions, we can't help but talk about Ruby's = ~ And match. Let's use an instance to illustrate the differences between the two matching methods. Let's talk about = ~ Usage:

 
 

  
  
message="afhadhffkdf414j" 
  
  
regex=/[a-z](\d{3})[a-z]/  
  
  
putsregex=~message  
  
  
message="afhadhffkdf414j" 
  
  
regex=/[a-z](\d{3})[a-z]/  
  
  
putsregex=~message 
 
 

In Ruby, the regular expression matching statement is expressed. You can run the preceding statement to match a string with lowercase letters on both sides of the three numbers. When we run the above Code, The result 10 will appear. You must be surprised, why is the result 10 ~ He is the first appearance position of the matching results to print out.

Let's take a look at the match:

 
 

  
  
message="afhadhffkdf414j" 
  
  
regex=/[a-z](\d{3})[a-z]/  
  
  
putsregex.match(message)  
  
  
 
  
  
message="afhadhffkdf414j" 
  
  
regex=/[a-z](\d{3})[a-z]/  
  
  
 
  
  
putsregex.match(message) 
 
 

Let's take a look at the output result: f414j. This string indicates all the result sets that match the regular expression. I don't know if you have noticed that we have used parentheses in the regular expression. We want to extract three numbers. Of course, this is also very simple. We only need to make some modifications in the above Code:

 
 

  
  
message="afhadhffkdf414j" 
  
  
regex=/[a-z](\d{3})[a-z]/  
  
  
regex.match(message)  
  
  
puts$1  
  
  
 
  
  
message="afhadhffkdf414j" 
  
  
regex=/[a-z](\d{3})[a-z]/  
  
  
regex.match(message)  
  
  
puts$1 
 
 

The result is 414. Why $1 instead of $0? Let's look at the result of $0.

 
 

  
  
C:/Users/Administrator/Documents/NetBeansProjects/RubyApplication1/lib/regex.rb
  
  
 
 
 

It is the output object information.

Next, a new situation occurs. Suppose a string contains a lot of information that complies with the rules. The preceding statement can only match the first result. What should we do if we print all the results? At the beginning, I was influenced by java and thought that the match result would be a set, so I didn't think about it. Later I found a scan method. The Code is as follows:

 
 

  
  
message="afhadhffkdf414j9tr3j43i3433094jwoert223jwew123dfdf" 
  
  
regex=/[a-z](\d{3})[a-z]/  
  
  
message.scan(regex).each{|m|puts"Theresultis#{m[0]}"}  
  
  
 
  
  
message="afhadhffkdf414j9tr3j43i3433094jwoert223jwew123dfdf" 
  
  
regex=/[a-z](\d{3})[a-z]/  
  
  
message.scan(regex).each{|m|puts"Theresultis#{m[0]}"} 
 
 

The result is:

 
 

  
  
Theresultis414  
  
  
Theresultis223  
  
  
Theresultis123  
  
  
 
  
  
Theresultis414  
  
  
Theresultis223  
  
  
Theresultis123 
 
 

It's very convenient. It's easy to extract all the matching results.