Title Requirements:
Given a positive integer in decimal, write down all integers starting with 1, to N, and then count the number of "1" that appears. Requirements: 1. Write a function f (n) and return the number of "1" that appears between 1 and N. For example F (12) = 5. 2. In the range of 32-bit integers, the maximum n of "f (n) =n" satisfying the condition is what.
first, the solution of ideasBy enumerating several numbers, we can find that the law of function f (n) is as follows: 1. A decimal number: When N>=1, f (n) = 1; When n=0, f (n) = 0; 2. Two-bit decimal number: f (13) = number of single-digit occurrences of 1 + 10-bit occurrence 1 =2+4=6; F (23) = digit 1 number + 10 digit appears 1 number =3+10=13; ... f (93) = number of digits appearing 1 + 10 digits appear 1 number =10+10=20; 3. Three-bit decimal number: f (123) = The number of single-digit occurrences of 1 + 10 digit appears 1 number + the number of 1 =13+20+24=57; 4.F (ABCDE), calculate the number of 1 on the C-bit, need to see the case of AB, C, de: When c=0, by the high influence, the hundreds appear 1 The number is: (AB) *100 when c=1, affected by high and low, the number of hundreds of 1 appears: (AB) *100+ (CDE) +1) when c>1, by the high influence, the number of 1 on the Hundred is: ((AB) +1) *100
Second, the program code
#include"stdafx.h"#include<iostream.h>#include"stdlib.h"intCountnum (intN) { intCount=0; intFactor=1; intlowernum=0; intcurnum=0; inthighernum=0; while(n/factor!=0) {Lowernum=n-(n/factor) *factor; Curnum= (n/factor)%Ten; Highernum=n/(factor*Ten); Switch(curnum) { Case 0: Count=count+highernum*factor; Break; Case 1: Count=count+highernum*factor + Lowernum +1; Break; default: Count=count+ (highernum+1)*factor; Break; } Factor=factor*Ten; } returncount;}intMain () {intnum; cout<<"Please enter a number: \ n"; CIN>>num; cout<<"\ n"; cout<<num<<"Number 1 appears in the number: \ n"; cout<<countnum (num) <<Endl; return 0;}
Iii. Results
Iv. ExperienceAt the beginning of the class to get this topic, the first reaction is to find the law, by some examples, special figures to observe, but at the beginning of the time because of too many, their own calculation of the time there was a mistake, very chaotic, and then after the teacher explained and classmates to discuss, find the direction of the law, calm again to calculate, This is to find out its laws, such as the law of the algorithm, must be calm, not irritable, not to give up.
Classroom Practice--Find the number 1 in the decimal number