A. Save Luke
Test instructions: Give a person the length of D, and then give an interval length of 0~l, give you two bullets of speed v1,v2, two bullets from 0 and L to the middle of the shot (actually not bullets, is a kind of film in the type of the tooth machine and so on is a person trapped in the inside, The one on either side that has a sharp thorn in the middle, and asks the longest time Luke can survive.
Idea: Look at the code, easy to understand
1#include <cstdio>2#include <cmath>3 intMain ()4 {5 intD,l,v1,v2;6 while(SCANF ("%d%d%d%d", &d,&l,&v1,&v2)! =EOF)7 {8printf"%.6lf\n", (l-d) *1.0/(v1+v2));9 }Ten}
B. Making a String
Test instructions: A26-letter string that gives you the number of letters and the number of letters that can be placed on each letter, with certain rules when you make a string:
1. The number of each letter in the string cannot be more than the given quantity
2. The number of occurrences of each letter in the string is different
What is the longest string of questions?
Idea: Because of the different elements involved, so use set to do,
First put a WA in the 20th set of data code
1#include <cstdio>2#include <cstring>3#include <cmath>4#include <algorithm>5#include <Set>6 using namespacestd;7 Long Longnum[ -],sum[ -];8 intMain ()9 {Ten intN; One while(SCANF ("%d", &n)! =EOF) A { - Set<Long Long>p; - Long Longtot=0; the for(intI=0; i<n;++i) -scanf"%lld",&num[i]); -Sort (num,num+n); - for(inti=n-1; i>=0;--i) { + while(P.find (num[i])! =P.end ()) { -num[i]-=1; + } A P.insert (Num[i]); attot+=Num[i]; - } -printf"%lld\n", tot); - } -}
This code, in the while Loop num[i] may be reduced to negative, so input 3 1 1 1 The answer would have been 0, but the output is 0
So we have to make a judgment on negative numbers.
1#include <cstdio>2#include <cstring>3#include <cmath>4#include <algorithm>5#include <Set>6 using namespacestd;7 Long Longnum[ -],sum[ -];8 intMain ()9 {Ten intN; One while(SCANF ("%d", &n)! =EOF) A { - Set<Long Long>p; - Long Longtot=0; the for(intI=0; i<n;++i) -scanf"%lld",&num[i]); -Sort (num,num+n); - for(inti=n-1; i>=0;--i) { + while((P.find (num[i])! =p.end ())) { -num[i]-=1; + } A if(num[i]<0) num[i]=0; at P.insert (Num[i]); -tot+=Num[i]; - } -printf"%lld\n", tot); - } -}
That's it.
Error code paste here is to remind yourself against a problem for their own code to do no loopholes can be found,
AIM Tech Round (Div. 2)