function overloading (cont.) = = "function overloading with function pointers

function overloading and function pointers (this piece is important, follow up to continue learning):

When you assign a value to a function pointer using the overloaded functions name

Selecting candidates that are consistent with the parameter list of a function pointer based on overloaded rules

The function types that match the candidate's function type and function pointer strictly

#include  <iostream>using namespace std;void myfunc (int a) {     printf ("a:%d\n", a);} Void myfunc (char *p) {    printf ("p:%s\n", p);} Void myfunc (int a,int b) {    printf ("a:%d\n", a);} function pointers   Underlying syntax//1  declares a function type//void myfunc (int a,int b) typedef void  (Mytypefunc) (int a,int b);//mytypefunc *myfuncp = null;//defines a pointer to a function that points to the entry address of the function//2  Declares a function pointer type typedef void  (*MYPTYPEFUNC) (int a,int b);//Declares a pointer function type//MYPTYPEFUNC&NBSP;FP  = null;   //defines a function pointer by using the function pointer type   defined//3  a function pointer   variable void  (myvarpfunc) ( INT&NBSP;A,INT&NBSP;B); Int main (int argc, char *argv[]) {     Myptypefunc fp = null;    fp = myfunc ();     FP (;    cout << ) "hello world!"&NBSP;&LT;&LT;&NBSP;ENDL;&NBSP;&NBSP;&NBSP;&NBSP;RETURN&NBSP;0;} 

Note Distinguishing function overloading overrides redefinition

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function overloading (cont.) = = "function overloading with function pointers