How do I obtain the area of the intersection of two transpose Rectangles?

Http://blog.csdn.net/yanleigis/article/details/3158223

How to calculate the area of the intersection of two intersecting Rectangles?
Is the public part of the handover area?

Class rectangle {
Point min;
Point Max;
}

Rectangle rect1, rect2;
Rectangle rect;

Locate the two values in the middle of the X coordinate.

Locate the two values in the Y coordinate.

Rect. Min. x = max (rect1.min. X, rect2.min. X); // find the largest X from the smallest x
Rect. Min. Y = max (rect1.min. Y, rect2.min. Y); // find the largest y from the smallest y
Rect. Max. x = min (rect1.max. X, rect2.max. X); // find the smallest X from the largest x
Rect. Max. Y = min (rect1.max. Y, rect2.max. Y); // find the smallest y from the largest y
If (rect. Min. x <rect. Max. X & rect. Min. Y <rect. Max. Y) // The intersection of area
S = (rect. Max. x-rect.min.x) * (rect. Max. y-rect.min.y)
Else
S = 0;

How to determine whether two rectangles are intersecting

Assume that the rectangle is expressed by a pair of vertices (Minx, miny) (Maxx,Maxy)

Then two rectangles rect1 {(minx1, miny1) (maxx1,Maxy1 )},
Rect2 {(minx2, miny2) (maxx2,Maxy2 )}

 
 The result of the intersection must be a rectangle that forms the rect {(Minx, miny) (Maxx,
Maxy)} Point-to-point coordinates are:
 Minx
=Max (minx1,
Minx2)
 Miny
=Max (miny1,
Miny2)
 Maxx
=Min (maxx1,
Maxx2)
 Maxy
=Min (maxy1,
Maxy2)
 
 If the two rectangles do not overlap, the calculated point-to-point coordinates must meet

 Minx
>Maxx

 Or

 Miny
>Maxy