In the sorted array look for two number a plus B equals given n

Source: Internet
Author: User

public class in the sorted array to find two number a plus b equals the given n {

public static void Main (string[] args) {


* Initialization parameter result is the resulting value

* num is the test array

* Start cursor, END cursor


int Result = 15;

int[] num = {1,2,4,7,11,15};

int start = 0, end = num.length-1;

Start sweep from both ends of the array, if the sum of the two numbers is less than the target, the head goes back in one, or the tail goes forward into a

while (Start < end) {

if (Num[start]+num[end]==result) {

System.out.println (Num[start] + "+" + num[end] + "=" + Result);


}else if (num[start]+num[end]<result) {


}else {






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In the sorted array look for two number a plus B equals given n

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