Jiangxi University of Science and technology new basic exercises (1)

This time the topic is hdu1089-1096 ( if you do the right, please turn to the last side )

1089 whatever you want.

#include <iostream>usingnamespace  std; int Main () {    int  N, M, K;      while (Cin >> m>>N)    {        = m + N;         << k << Endl;    }     return 0 ;}

1090 as well.

#include <iostream>usingnamespace  std; int Main () {    int  n;    CIN>>N;     int b;      for (;n>0; n--)    {            cin>>a>>b;            cout<<a+b<<endl;    }     return 0 ;}

1091 Notice the end condition

#include <stdio.h>intMainintargcChar Const*argv[]) {  intb; scanf ("%d%d",&a,&b);  while(a!=0|| b!=0) {printf ("%d\n", A +b); scanf ("%d%d",&a,&b); }  return 0;}

1092 or pay attention to the end condition

 #include <iostream>using  namespace   Std;  int   Main () { int      A,b,n;     for  (;(cin>>n) &&n;) { for  (A=0 ; N>0 ; N-- >>b;            A  +=B;    } cout  <<a<<ENDL;  return  0  ;}

1093 nothing changed, just add a T-Group of data

#include <stdio.h>intMainintargcChar Const*argv[]) {  intN;  while(SCANF ("%d", &n)! =EOF) {     for(size_t i =0; I < n; i++) {      intTotal=0, B,a; scanf ("%d",&b);  for(size_t i =0; I <b; i++) {scanf ("%d",&a); Total+=A; } printf ("%d\n", total); }  }  return 0;}

1094

#include <iostream>usingnamespace  std; int Main () {    int  a,b,n;      while (cin>>N)    {        for (a=0; n>0; n--)        {            cin>>b;            A+ =b;        }        cout<<a<<endl;    }     return 0 ;}

1095 for two lines, that's right.

#include <iostream>usingnamespace  std; int Main () {    int A, b;      while (cin>>a>>B)        cout<<a+b<<endl<<Endl;     return 0 ;}

1096 Note that the last set of data is a newline, we can use a count t to now process to the first group of data, and then the last line of a line

The code that was written a long time ago

#include <stdio.h>intMainvoid){    intn,i,sum,m,temp; scanf ("%d",&N);  while(N) {scanf ("%d",&M); Sum=0;  for(i=0; i<m; i++) {scanf ("%d",&temp); Sum+=temp; }        if(n!=1) printf ("%d\n\n", sum); Elseprintf ("%d\n", sum); N--; }    return 0;}

UVA 10055 It's very easy to read test instructions.

 #include <stdio.h> #include  <iostream>  #include  <algorithm>using  namespace   Std;  int  Main (int  argc, char  const  *argv[]) { long  long   A, b;  while  (Cin>>a>>b) {cout<<abs (A-B) <<ENDL;  return  0  ;}

UVA 100,711 Physics topics, difficulty is not university physics

 #include <stdio.h> #include  <iostream>  #include  <algorithm>using  namespace   Std;  int  Main (int  argc, char  const  *argv[]) { long  long   A, b;  while  (Cin>>a>>b) {cout<<2  *a*b<<ENDL;  return  0  ;}

UVA 10300 Read Test instructions, we know only ask area * friendly and on the line

#include <stdio.h>#include<iostream>#include<algorithm>using namespacestd;intMain () {intT,n; intSquare,animal,enfriend; CIN>>T;  while(t--) {cin>>N; intsum=0;  while(n--) {cin>>square>>animal>>Enfriend; Sum+ = (square*enfriend); } cout<<sum<<Endl; }    return 0;}

Jiangxi University of Science and Technology new basic exercise (1)