Learning << Assembly language-Wang Shuang >> This book a period of time, self-completed a real question

application of seven-way approach in structured data access (172th page of the book)

Experimental content

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The data is already defined in the following program:

assume Cs:code SG

Data segment

DB'1975','1976','1977','1978','1980','1980','1981','1982','1983'

DB'1984','1985','1986','1987','1988','1989','1990','1991','1992'

DB ' 1993 ' , ' 1994 ' , ' 1995 '

The above is a string that represents seven years (4 bytes per string)

DD 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514

DD 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000

Above is a DWORD Data ( 4 bytes each) representing the company's total revenue for the year

DW 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226

DW 11542,14430,15257,17800

The above is the word data (2 bytes each) that represents the number of employees in the company for a year .

Data ends

Table Segment

db DUP (' year summ ne?? ' )

Table Ends

Code SG segment

Start

Code SG ends

End Start

programming: data annual per capita income ( rounding )

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Here is the complete code for my answer:

:>----------------------------------------------------------------------------------------

Assume CS:CODESG

Data segment

DB ' 1975 ', ' 1976 ', ' 1977 ', ' 1978 ', ' 1979 ', ' 1980 ', ' 1981 ', ' 1982 ', ' 1983 '

DB ' 1984 ', ' 1985 ', ' 1986 ', ' 1987 ', ' 1988 ', ' 1989 ', ' 1990 ', ' 1991 ', ' 1992 '

DB ' 1993 ', ' 1994 ', ' 1995 '

DD 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514

DD 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000

DW 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226

DW 11542,14430,15257,17800

Data ends

Stack segment

DW 0,0,0,0,0,0,0,0; To better understand the stack, the stack is used to hold the data

Stack ends

Table Segment

DB DUP (' Year Summ ne?? ‘)

Table Ends

CODESG segment

Start:mov ax, data; Initialize DS segment Register to data

MOV ds, ax

mov ax, table; Initialize the ES segment register to table

MOV es, ax

mov ax, stack; initialize SS segment register to Stack

mov ss, ax

mov sp, 10H; initialize SS-Stack-segment pointer sp

MOV bx, 0; Use BX to control the row movement of table data, move 16 bytes at a time

mov bp, 0; Use BP to point to the first address of the Data section data (Additional function: staging the stack data)

mov si, 0; Use SI to move the data segment with BP

mov di, 0; Use di to move the first address of each column of data with BX to access each row of the table

Push Si first into the stack because SI is used to move the data in and out, but the date data and the total revenue

The amount of data moved is 4 bytes, and the number of employees is 2 bytes, in order to use

Si to unify the operation, so think of using the stack to save Si to take the average income of the movement.

mov cx, 15H; CX controls row Movement to table (total 21 rows =15h)

S0:mov ax, [si]

MOV dx, [si].2h

MOV ES:[BX], ax

mov es:[bx].2h, DX

The above is the date data that is re-created into data into the ' year ' of each row in the table

MOV bp, 54H

mov di, 5H

mov ax, Ds:[bp][si]

MOV dx, ds:[bp][si].2h

MOV Es:[bx][di], ax

mov es:[bx][di].2h, DX

The above is the ' Summ ' of the date data in the database to each row in the table

Pop bp

Push SI

mov si, bp

; Take out the moving amount of the average income of SI 2, and save the SI with a moving volume of 4

MOV bp, 0a8h

mov di, 0DH

div word ptr ds:[bp][si]

MOV Es:[bx][di], ax

Calculate the average income and save it to the '?? ' in each row of the table.

mov di, 0AH

mov ax, Ds:[bp][si]

MOV Es:[bx][di], ax

Copy the number of company employees from data and save to ' ne ' in each row of the table

Add Si, 2H; the current Si-per-2 movement (as the number of SI operable data)

Pop bp

Push SI

mov si, bp

The above is to change SI to 4 each time the movement (that is, si to the operating date, income data), and will

Si each add 2 of the moving amount into the stack to save

Add Si, 4H; the current Si movement of 4 (SI operable date, data portion of income data)

Add bx, 10H; jumps to the first address of the next line of table

loop S0; Repeat the above operation

mov ax, 4c00h

int 21H

CODESG ends

End Start

:<-----------------------------------------------------------------------------------------

The following is the data in the post-run table segment and the corresponding ASCII code representation:

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Summarize:

Code is a bit long, because it is still just a short time, but the whole experiment to do down the table in memory of the preservation has a very clear understanding, continue to refuel learning! If everyone has a better code welcome to share.

-------------The above exercises section and code reference Yu Wang Teacher's << assembly language >> Second Edition----------------

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Learning << Assembly language-Wang Shuang >> This book a period of time, self-completed a real question