Network ID matching of the parity ACL

The network number of the parity ACL matches the network number of the experiment TOPO: www.2cto.com. The experiment requires that: with ACL, route-map and re-release, R1 can only learn the network number of odd digits or even digits, that is, the x of 192.168.x.0 is odd or even. step 1: configure the IP addresses of each vro and confirm that the direct interface can be pinged. tutorial Step 2: configure the RIP and OSPF protocols, and the network has the correct network interface, and pay attention to the use of passive-interface experiment Step 3: Configure re-release on R2, confirm that the network can be learned to all networks through republishing. analysis of question requirements: www.2cto.com R1 can only learn the network number of the odd number or even number of R3. split the subnets into binary values and observe the rule 192.168.1.0/24 192.168.0000 0001.0/24192.168.2.0/24 192.168.0000 0010.0/24192.168.3.0/24 192.168.0000 0011.0/24192.168.4.0/24 192.168.0000 0100.0/24192.168.5.0/24 192.168.0000 0101.0/24192.168.6.0/24 192.168.0000 0110.0/24192.168.7.0/24 192.168.0000 0111.0/24192.168.8.0/24 192.168.0000 1000.0/24, if x of 192.168.x.0/24 is an even number, the 24th bits are 0. If the value is odd, the 24th bits are 1, therefore, according to this rule, the 0 of the ACL is completely matched. 1 indicates that the matching rule is ignored. The following two ACLs can be written to match the 24th bits. network number used for even digits: access-list 1 permit 192.168.0.0 0.0.254.0192.168.0000 2.16.0000.000.1111 1110.0 network number used for odd digits: acces S-list 2 permit 192.168.1.0 0.0.254.0192.168.0000 0001.0000.000.1111 1110.0 experiment practice 1: Configure on R2 to test the matching of even bits: access-list 1 permit 192.168.0.0 0.0.254.0! Route-map parity-acl permit 10 match ip address 1! Router ospf 1 redistribute rip subnets route-map parity-acl view the route table on R1 and find that there is only an even number of network numbers: O E2 192.168.8.0/24 [110/20] via 172.16.1.2, 00:00:38, serial1/1O E2 192.168.4.0/24 [110/20] via 172.16.1.2, 00:00:38, Serial1/1O E2 192.168.6.0/24 [110/20] via 172.16.1.2, 00:00:38, serial1/1O E2 192.168.2.0/24 [110/20] via 172.16.1.2, 00:00:38, Serial1/1 experiment practice 2: no drops the configured acl and route-map, and configures it on R2, test odd-digit matching access-list 2 permi T 192.168.1.0 0.0.254.0! Route-map parity-acl permit 10 match ip address 2! Router ospf 1 redistribute rip subnets route-map parity-acl view the route table on R1 and find that there is only a network number of odd digits: O E2 192.168.5.0/24 [110/20] via 172.16.1.2, 00:00:27, serial1/1O E2 192.168.7.0/24 [110/20] via 172.16.1.2, 00:00:27, Serial1/1O E2 192.168.1.0/24 [110/20] via 172.16.1.2, 00:00:27, serial1/1O E2 192.168.3.0/24 [110/20] via 172.16.1.2, 00:00:27, Serial1/1