Nyoj question 10 skiing -- Nanyang OJ

Title information is as follows: skiing time limit: 3000 MS | memory limit: 65535 kb difficulty: 5

Description

It's not surprising that Michael loves skiing because skiing is really exciting. But in order to get the speed, the slide area must be tilted down, and when you slide to the bottom, you have to go uphill again or wait for the elevator to carry you. Michael wants to know the longest landslide in a region. A region is given by a two-dimensional array. Each number in the array represents the vertex height. The following is an example.
1 2 3 4 5

16 17 18 19 6

15 24 25 20 7

14 23 22 21 8

13 12 11 10 9

A person can slide from a certain point to one of the four adjacent points up and down, when and only when the height is reduced. In the preceding example, a slide is 24-17-16-1. Of course, 25-24-23-...-3-2-1 is longer. In fact, this is the longest one.

Input

The first row indicates the number of test data sets. The second row indicates the number of rows in the region R and the number of columns C (1 <= r, C <= 100 ). Below is the R row, each row has a C integer, representing the height H, 0 <= H <= 10000.
The following is the next group of data;

Output

The length of the maximum output area.

Sample Input

15 51 2 3 4 516 17 18 19 615 24 25 20 714 23 22 21 813 12 11 10 9

Sample output

25

The source code is as follows:

#include<stdio.h>int N,HIGH,WIDTH,Max=0;int a[101][101];void skiing(int m,int n,int t){if (m-1 >=0){if (a[m-1][n] < a[m][n]) skiing(m-1,n,t+1);}if (m+1 < HIGH){if (a[m+1][n] < a[m][n]) skiing(m+1,n,t+1);}if (n-1 >= 0){if (a[m][n-1] < a[m][n]) skiing(m,n-1,t+1);}if (n+1 < WIDTH){if (a[m][n+1] < a[m][n]) skiing(m,n+1,t+1);}if (t > Max) Max = t;}int main(){int i,j;scanf("%d",&N);while(N--){Max = 0;scanf("%d%d",&HIGH,&WIDTH);for (i=0; i < HIGH;i++)for (j=0; j < WIDTH; j++)scanf("%d",&a[i][j]);for (i=0; i < HIGH;i++)for (j=0; j < WIDTH; j++)skiing(i,j,1);printf("%d\n",Max);}return 0;}

Nyoj question 10 skiing -- Nanyang OJ