Oracle + hibernate insert time

1. The insert format is.

<Property name = "artAddTime" type = "java. util. Date">

<Column name = "ART_ADD_TIME" length = "7" not-null = "true"/>

</Property>

/**

* Write a time Method

*/

Public staticStringgetStringDate (){

Date d = new Date ();

SimpleDateFormat sdf = new SimpleDateFormat ("yyyy-MM-dd ");

Return sdf. format (d );

}

Insert:

Art. setArtAddTime (java. SQL. Date. valueOf (new TimeUtil (). getStringDate ()));

Dao. save (art );

="

Art. setArtAddTime (java. SQL. Date. valueOf ("2009-12-12 "));

However, the output value in the Java background is as follows: 00:00:00. 0

2

Insert hours, minutes, And seconds

<Property name = "artAddTime" type = "timestamp"> Date is also supported.

<Column name = "ART_ADD_TIME" not-null = "true"/>

</Property>

Art. setArtAddTime (java. SQL. Timestamp. valueOf (new TimeUtil (). getStringDate ("yyyy-MM-dd HH: mm: ss ")));

Output: 2010-12-1223:49:48. 0 Java output is still one more bit

3. If Oracle is 10 Gb, skip the above steps.

<Property name = "artAddTime" type = "timestamp"> Date is also supported.

<Column name = "ART_ADD_TIME" not-null = "true"/>

</Property>

Art. setArtAddTime (new Date ());

Out: 23:49:48. 0