Printf ("% * s", 4, "*****" + 4); Explanation

Printf ("% * s", 4, "*****" + 4); Explanation

Printf ("% * s/n", 6, "******" + 0); explains // adding a Baidu to favorites and is useful to you!

1. Start with % * s. The format behind the % of printf is:
% [Flags] [width] [. Precision] [{H | L | ll | I | i32 | i64}] Type

For detailed usage of these parameters, see msdn:
Http://msdn2.microsoft.com/en-us/library/56e442dc (vs.80). aspx

Here I will only focus on: [width] and [. precision] If "*" is used, the two values are an input parameter, because in this example, % * s is not %. * s, so it is certain that this * represents [width] ([flags] cannot be expressed ).

The [width] parameter indicates a width. If the input string is small and cannot be of this width, it is filled with the value of the [flags] parameter. If [flags] is empty, fill in with spaces.

In this example, [width] = 4. Therefore, if the % s string is smaller than 4, spaces will be filled before.

2. "*****" + 4, indicating what, in C string "********" indicates a pointer address, "******" + 4 indicates this pointer + 4, so the result is a "*". You can try "******" + 1, and "abcdf" + 4. The result is "*****" and the result is "F ".
If you do not understand it, try the following program:
Char * Ss = "abcdf ";
Printf ("% s, % s", SS, SS + 1, SS + 2, SS + 3, SS + 4 );

Conclusion: This printf indicates printing a string. If there are less than 4 strings, fill them with spaces. The actual address of the string is "*****" + 4, that is, print the result at the location of 4th "*"

========================================================== =
Printf ("% * s/n", 6, "*****" + 0 );
The output length is less than 6 and 6 spaces are filled in. Now you have 5 x spaces. Therefore, you only need to fill in one space.

Printf ("% * s/n", 6, "*********" + 0 );
This space does not exist, all of which are *. If the length is insufficient, the space is filled.

 

 

 

 

Ch = "123456780123 ";
Int n = 2, M = 10;
// *. *, The front side * defines the total width, and the back side defines the number of outputs.
// If the back side is smaller than the front side, use spaces to fill up M places on the left side.
Printf ("% *. * s/n", M, N, CH); // output "12" here"
Printf ("% *. * s/n", n, m, CH); // output "1234567890" here"

Printf ("% * s/n", 6, "******" + 0); explains // adding a Baidu to favorites and is useful to you!

1. Start with % * s. The format behind the % of printf is:
% [Flags] [width] [. Precision] [{H | L | ll | I | i32 | i64}] Type

For detailed usage of these parameters, see msdn:
Http://msdn2.microsoft.com/en-us/library/56e442dc (vs.80). aspx

Here I will only focus on: [width] and [. precision] If "*" is used, the two values are an input parameter, because in this example, % * s is not %. * s, so it is certain that this * represents [width] ([flags] cannot be expressed ).

The [width] parameter indicates a width. If the input string is small and cannot be of this width, it is filled with the value of the [flags] parameter. If [flags] is empty, fill in with spaces.

In this example, [width] = 4. Therefore, if the % s string is smaller than 4, spaces will be filled before.

2. "*****" + 4, indicating what, in C string "********" indicates a pointer address, "******" + 4 indicates this pointer + 4, so the result is a "*". You can try "******" + 1, and "abcdf" + 4. The result is "*****" and the result is "F ".
If you do not understand it, try the following program:
Char * Ss = "abcdf ";
Printf ("% s, % s", SS, SS + 1, SS + 2, SS + 3, SS + 4 );

Conclusion: This printf indicates printing a string. If there are less than 4 strings, fill them with spaces. The actual address of the string is "*****" + 4, that is, print the result at the location of 4th "*"

========================================================== =
Printf ("% * s/n", 6, "*****" + 0 );
The output length is less than 6 and 6 spaces are filled in. Now you have 5 x spaces. Therefore, you only need to fill in one space.

Printf ("% * s/n", 6, "*********" + 0 );
This space does not exist, all of which are *. If the length is insufficient, the space is filled.

 

 

 

 

Ch = "123456780123 ";
Int n = 2, M = 10;
// *. *, The front side * defines the total width, and the back side defines the number of outputs.
// If the back side is smaller than the front side, use spaces to fill up M places on the left side.
Printf ("% *. * s/n", M, N, CH); // output "12" here"
Printf ("% *. * s/n", n, m, CH); // output "1234567890" here"