printf ("%*s", 4, "* * *" +4);

printf ("%*s", 4, "* * *" +4);
printf ("%*s/n", 6, "* * *" +0); Explain/collect Baidu a problem, a bit of use for yourself.

1. As explained first from%*s, the following format for the% printf is:
%[flags] [width] [. precision] [{h | l | ll | I | I32 | I64}]type

For detailed usage of these parameters, refer to MSDN:
HTTP://MSDN2.MICROSOFT.COM/EN-US/LIBRARY/56E442DC (vs.80). aspx

Here's what I'm talking about: the parameter [width] and the parameter [. Precision] If you use * to represent the two values is an input parameter, because in this case the%*s is not%.*s, so you can be sure that this * represents [width] ([flags] cannot be represented by *).

The [width] parameter represents a width, and if the input string is small and less than this width, it is populated with the value of the flags parameter, and if [flags] is empty, fill with a space.

In this example [width]=4, so if the string for%s is less than 4, then padding is preceded by a space.

2. "* * *" +4, what is that, in C the string "Hu-hu" represents a pointer address, "+4" is the pointer +4, so the result is a "*", you can try "* * *" +1, and "ABCDF" +4, the result is a "* * *", One is "f".
If you don't understand, try the following procedure:
Char *ss= "ABCDF";
printf ("%s,%s,%s,%s,%s", ss,ss+1,ss+2,ss+3,ss+4);

Summary: This printf represents: print a string, if the string is less than 4, padded with blanks, the fact that the address of the string is "* * *" +4, that is, the 4th "*" position, print the result "*"

=========================================
printf ("%*s/n", 6, "* * *" +0);
The output length is less than 6, padded with 6 spaces, and now your * has 5, so just fill a space.

printf ("%*s/n", 6, "********" +0);
This is not a single space, all is *, the length is insufficient to fill, and is missing how much

ch   =   "123456780123";  
    int   n   =   2,m   =  ;  
   //*.*  , the front is defined as the total width, and the number of outputs is defined in the rear.  
   //If the rear is smaller than the front, use a space to make up M-bit on the left.  
    printf ("%*.*s/n", m,n,ch)//Here Output "               " &nbs P
    printf ("%*.*s/n", n,m,ch);//Here Output "1234567890"