Probability generator (generate uniform and non-uniform 0, 1)

Programs that generate a probability of 0 and 1 can be adjusted according to the settings:

#include <stdio.h>#include <stdlib.h>int EqualProbability() {  if (rand() % 2 == 0) {    return 0;  } else {    return 1;  }}int BiasProbability(int parameter) {  int size = parameter + 1;  if (rand() % size == 0) {    return 0;  } else {    return 1;  }}int main(int argc, char** argv) {  int zero_counter = 0;  int one_counter = 0;  const int kGenerateTime = 1000000;  for (int i = 0; i < kGenerateTime; ++i) {    if (EqualProbability() == 0) {      zero_counter++;    } else {      one_counter++;    }  }  printf("zero:%d one:%d\n", zero_counter, one_counter);  zero_counter = 0;  one_counter = 0;  for (int i = 0; i < kGenerateTime; ++i) {    if (BiasProbability(10) == 0) {      zero_counter++;    } else {      one_counter++;    }  }  printf("zero:%d one:%d\n", zero_counter, one_counter);}

Related questions:

Known as a random generator, the probability of generating 0 is P, and the probability of generating 1 is 1-P. Now you need to construct a generator,
So that the probability of constructing 0 and 1 is 1/2. Construct a generator so that the probability of constructing 1, 2, and 3 is 1/3 ;...,
Construct a generator so that the probability of constructing 1, 2, 3,... n is 1/N, requiring the lowest complexity.

For n = 2, 01 indicates 0, 10 indicates 1, and other probabilities. In other cases, discard

For n = 3, 001 indicates 1, 010 indicates 2,100 indicates 3, and other probabilities.

For N = 4, think 0001 represents 1, 0010 represents 2, 0100 represents 3, represents 4, and other probability, other circumstances give up