"Codeforces 353 A" Domino

"Link" I am the link, point me:)
Test instructions

Exercises

Category discussion a wave
Sets the odd number of the first array to Cnt1
The odd number of the second array is Cnt2
Obviously only in the case of (Cnt1+cnt2)%2==0.
It is possible for the first array to be even, and the second array to be even.
(because odd numbers have to appear even several times to do so.)
So it's only possible that cnt1 and cnt2 are even, so output 0
Otherwise, cnt1 and Cnt2 are odd, see if there is a position I only a[i] or only b[i] is odd. Some words output 1.
Other cases are illegal.

Code

#include <bits/stdc++.h>using namespace std;const int N = 1e2;int n;int x[N+10],y[N+10],cnt1,cnt2;int main(){    #ifdef LOCAL_DEFINE        freopen("rush.txt","r",stdin);    #endif // LOCAL_DEFINE    ios::sync_with_stdio(0),cin.tie(0);    cin >> n;    for (int i = 1;i <= n;i++){        cin >> x[i] >> y[i];        if (x[i]&1) cnt1++;        if (y[i]&1) cnt2++;     }     if (cnt1%2==0 && cnt2%2==0){        cout<<0<<endl;     }else if ( (cnt1+cnt2)%2 != 0){        cout<<-1<<endl;     }else{        //cnt1+cnt2 == not odd        for (int i = 1;i <= n;i++){            if (x[i]&1 && y[i]%2==0)                return cout<<1<<endl,0;            if (x[i]%2==0 && y[i]&1)                return cout<<1<<endl,0;        }        cout<<-1<<endl;     }    return 0;}

"Codeforces 353 A" Domino