Rokua P3374 "template" Tree array 1

Source: Internet
Author: User

Title Description

Title, you need to perform the following two operations, known as a sequence:

1. Add a number to the X

2. Find out the amount of each number in a range and

Input/output format

Input format:

The first line contains two integers n, M, respectively, indicating the number of numbers and the total number of operations.

The second line contains n space-delimited integers, where the I number represents the initial value of item I of a sequence.

The next M line contains 3 or 4 integers, representing an operation, as follows:

Action 1: Format: 1 x k Meaning: Add x number plus K

Action 2: Format: 2 x y meaning: the and of each number in the output interval [x, y]

Output format:

The output contains several line integers, which is the result of all Operation 2.

Input and Output Sample input example # #:
5 51 5 4 2 31 1 32 2 51 3-11 4 22 1 4
Sample # # of output:
1416
Description

Time limit: 1000ms,128m

Data size:

For 30% data: n<=8,m<=10

For 70% data: n<=10000,m<=10000

For 100% data: n<=500000,m<=500000

Sample Description:

Therefore, the output results 14, 16

1#include <iostream>2#include <cstring>3#include <cstdio>4 using namespacestd;5 intn,m,a[500010],tarr[500010];6 voidAddintPosintdel)7 {8     9      while(pos<=N)Ten     { Onetarr[pos]+=del; Apos+= (pos^ (pos-1)) &Pos; -     } -      the } - intQry (intPOS) - { -     intsum=0; +      while(POS) -     { +sum+=Tarr[pos]; Apos-= (pos^ (pos-1)) &Pos; at     } -     returnsum; - } - intMain () - { -Cin>>n>>m; in      for(intI=1; i<=n;i++) -scanf"%d",&a[i]); to      for(intI=1; i<=n;i++) + Add (I,a[i]); -     intflag,x,y; the      for(intI=1; i<=m;i++) *     { $scanf"%d%d%d",&flag,&x,&y);Panax Notoginseng         if(flag==1) Add (x, y); -         Elseprintf"%d\n", Qry (y)-qry (X-1)); the     } +      A     return 0; the}

Idea: Tree-like array back version ~ ~ ~

Rokua P3374 "template" Tree array 1

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