palm tree template

;if(!rc[u]) rc[u]=++p;u=rc[u];} } s[u]+=v; }}ii kth (R p,r k) {//Ask for a small value of KR i,l=1, r=l,m,sum,pa=0. p1=0; for(i=qr[p]; i;i-=i-i) ra[++pa]=rt[i]; for(I=ql[p]-1; i;i-=i-i) Rs[++ps]=rt[i]; while(L^R) {sum=0; m= (L+r) >>1; for(i=1; i for(i=1; iif(k for(i=1, p=pa,pa=0; i for(i=1, p=ps,ps=0; iElse{L=m+1; k-=sum; for(i=1, p=pa,pa=0; i for(i=1, p=ps,ps=0; ireturnB[L];} II rank (R p,r x) {//To rank the value after discretization (from 0, that is, the number of numbers less than or equa

Balance Tree Treap template and principle, tree treap Template This time, let's talk about Treap (splay later) The Balance Tree is a Sort binary tree (or binary search tree), so the sor

weight of each commodity, where the I integer represents the weight of the commodity labeled I weight_i.The 3rd behavior of each set of test data is an integer q, which indicates the sum of the number of times that a small hi has been queried and the number of times the weight of the product has been changed.Each group of test data n+4~n+q+3 line, each line describes an operation, each line begins with a number belonging to 0 or 1, respectively, indicating that the line describes a query and de

P3366 [TEMPLATE] Minimum Spanning Tree and p3366 template Spanning TreeDescription For example, an undirected graph is given to find the Minimum Spanning Tree. If the graph is not connected, the output is orz.Input/Output Format Input Format: The first line contains two integers N and M, indicating that the graph has

Minimum Spanning Tree template, spanning tree Template Prim: # Include

], j=pre[j], vis[j]=flag[j]=true;//points within the ring, and directly to the weight of the ring to add and record, after the last to find the smallest tree figure, no need to expand the contraction point } while (j!=i); Flag[i] = false; The ring shrinks into point I, the point I still exists4, the processing shrinkage point formed after the diagram: for (int k=1; kAfter processing 4, we go back to step 1, continue to find

Luogu P3919 [Template] can persist array (persisted segment tree/Balance Tree) topic#include #include#include#include#include#include#include#include#include#include#defineRG Register#defineIl inline#defineLST Long Long#defineN 1000050using namespacestd;intn,q,cnt;intVal[n];intRoot[n];structtree{intLs,rs,v;} Ljl[n* -];ilintRead () {RGints=0, m=1; RGCharCh=GetChar

+1, hash+tmp+1); Tot=std::unique (hash+1, hash+tmp+1)-(hash+1); for(intI=1; i) {A[i]=std::lower_bound (hash+1, hash+tot+1, A[i])-Hash; Bit::add (I,a[i],1); } for(intI=1; i) if(e[i].op!=2) E[i].opk=std::lower_bound (hash+1, hash+tot+1, E[I].OPK)-Hash; } voidsolve () { for(intI=1; i) { if(e[i].op==1) printf ("%d\n", Bit::qrank (e[i].opl-1, E[I].OPR,E[I].OPK,0)+1); Else if(e[i].op==2) printf ("%d\n", Bit::qnum (e[i].opl-1, E[I].OPR,E[I].OPK)); Else if(e[i].op==3

Rujia: "Training Guide" Page (194)#include Tree Array (binary index tree BIT Fenwick Tree) * "One-dimensional base template" (query interval and + modify update)

#include Talk about tree---No root tree go to a root tree (Dfs search conversion +FA array Record parent node) * "Template"

contains, numbers:n-the number of hubs in the network (2 OutputOutput first the maximum length of a cable in your hub connection plan (the value of your should minimize). Then output your Plan:first output p-the number of cables used and then output P pairs of an integer numbers-numbers of hub s connected by the corresponding cable. Separate numbers by spaces and/or line breaks.Sample Input4 61 2 11 3 11 4 22 3 13 4 12 4 1Sample Output141 21 32) 33 4Title Analysis: The original topic of Peking

Topic Link: Click to enterThe partition tree solves the problem of fast seeking the K-value of the interval, the main idea of the algorithm is based on the dividing method of segment tree and fast row, which can realize the K-value of any interval in logn time. The following code is a template based on the hud4251.The code is as follows:#include #include #include

; + intMain () { Ascanf"%d%d",n,m); at for(i=1; i){ -scanf"%d",t); - Add (i,t); - } - for(i=1; i){ -scanf"%d",f); in if(f==1){ -scanf"%d%d%d",x,y,k); to Update (X,Y,K); + } - Else{ thescanf"%d",x); *printf"%d\n", query (x)); $ }Panax Notoginseng } - return 0; the } + voidAddintPintx) { A while(pN) { thec[p]+=x; +p+=p-p; - } $ } $ voidUpdateintAintBintx) { - while(b>=a) {//interval plus -addv[b]+=x; theb-=b-b; - }Wuyia--; the

two cities to reach each other at least the required construction costs through the roads they build. Sample input Sample output 4178 vector variable-length arrays can emulate adjacency tables, but when this storage structure is used to process multiple sets of data, it is important to empty the vector array otherwise, Inevitable wa! Code: #include The #1097 of Hihocoder: minimum spanning

[Integration] matrix tree theorem template and matrix theorem Template Tree theorem survival tree counting template.Original question: SPOJhighwaysCode is long and ugly... # Include Copyright Disclaimer: This article is an original article by the blogger and cannot be rep

of the pointer, when the training is not willing to listen to the teacher, in a lot of words to write the algorithm application of the pointer implementation. At leastFor the use of one-level pointers is still possible!In the afternoon, we analyzed the trie array implementation algorithm in the Rujia Training guide for a long time. Not very understand, waiting to continue! Finally, I decided to write the pointer.Code: #include Hihocoder #1014: Trie

minn[101],g[101][101],u[101]; memset (U,1,sizeof(U)); memset (Minn,0x7f,sizeof(Minn)); minn[1]=0; u[1]=0; i,j,k,m; Total=0; for(i=1; i) {k=0; for(j=1; j) if(u[j] (minn[k]>Minn[j])) K=J; U[K]=0; for(j=1; j) if(u[j] (g[k][j]Minn[j])) MINN[J]=g[k][j];} for(i=1; i) Total+=Minn[i];coutEndl;/*Prim*/structedge{intX,y,v;} a[1001];intf[1001];intFindintx) { if(Find (x) ==x)returnx; F[X]=find (x); returnf[x];} Unionn (intXinty) { intHasfind (x); intfb=find (y); if(fa!=FB) F[FA]=FB;}intcmpCon

A long time ago to learn what is a flower tree, today did a set of questions, finally looked at, but the current level is to understand its general thinking, as to the details of implementation, is really powerless.Here are a few explanations for the blog:An algorithm with Flower tree for non-direction graph matchingWith Flower tree (general Graph maximum match)I

1#include 2#include 3#include 4#include 5#include 6#include 7 8#include 9#include string>Ten#include One#include A#include - - using namespacestd; the - voidAddint,int); - intPreint); - + intc[500010]; - + inti,n,m; A at intT; - - intK; - - intp,x; - intb; in - intMain () { toscanf"%d%d",n,m); + - for(i=1; i){ thescanf"%d",t); * Add (i,t); $ }Panax Notoginseng - for(i=1; i){ thescanf"%d",k); + if(k==1){ Ascanf"%d%d",p,x); the Add (p,x); + } -

+ = tree[r^1]; * } $ returnans;Panax Notoginseng } - intMainvoid){ then = Read (), M =read (); + build (); A while(m--){ the intopt = read (), x = Read (), y =read (); + if(opt==1) update (x, y); - Elseprintf"%d\n", Sum (x, y)); $ } $ return 0; -}zkw Segment Tree1#include 2 using namespacestd;3 4 #defineLowbit (a) a (a)5 6 Const intN =500010;7 8 intA[n], N, M, X, Y, K;9 TenInlinevoidUpdateintXintk) { One