Self-discovery of mathematical law One

Mathematical Law One

% is to take the remainder operation

123% 9 = 6

(1+2+3)% 9 = 6

3456795% 9 = 3

(3+4+5+6+7+9+5)% 9 = 3

(-123)% 9 = 3

[-(1+2+3)]% 9 = 3

The divisor will be credited as a1a2a3 ... An, the divisor is 9, the remainder is recorded as Q.

Then there are:

A1a2a3 ... An% 9 = Q1

(a1+a2+a3+...+an)% 9 = Q2

(-a1a2a3 ... AN)% 9 = Q3

[-(A1+a2+a3+...+an)]% 9 = Q4

Rule 1:q1 = Q2; q3 = Q4

Any integer number divided by 9 to get the remainder, equal to the sum of the numbers on each of the integers divided by 9 to get the remainder. This law is only established when the divisor is 9 , and when the divisor is 8,7 and other values, this rule is not established. If the integer number is negative, then the sum of the values on each of you is first asked, then the sum multiplied by ( -1) becomes negative, the integer number divided by 9, the remainder is still equal to the sum of the numbers of the integers (multiplied by ( -1) Minus) divided by 9 to get the remainder .

Self-discovery of mathematical law One