Shell get file suffix

Introduce a file in a makefile file by using include

Include $ (shell./getname)

and the contents of the GetName are as follows:

pwd=$ (PWD);

if ["${pwd#*/zloader.}" = "$pwd"];then

Echo Makefile.cpci

Else

echo Makefile.${pwd#*/zloader.}

fi

I've never read ${pwd#*/zloader.} What does this mean, and then it turns out that what you get is the suffix name of the make file.

If it's pwd=/xxx/yyy/zloader.bios, then you need to get Makefile.bios, where ${pwd#*/zloader.} = BIOS. Where ${AAA#BBB} is a regular expression, and '/* ' represents all of the preceding Zloader in the path string in the PWD.

Explain:

${parameter#pattern}

Substitute the value of parameter with patternremoved to the left side. The smallest portion of the contents of parametermatching pattern is removed. Shell filename substitution characters (*,?, [...],!, and @) May is used in.

Try a script under Linux to prove it.

#!/bin/sh

Mkdir-p Zloader./xxdir

CD Zloader./xxdir

pwd=$ (PWD)

echo "pwd = $pwd"

echo "This'll substitue pwd about the Patternzloader., into NULL"

echo "${pwd#*/zloader.}"

Cd.. /..