Qtree2-query on a tree IINo Tags
You were given a tree (an undirected acyclic connected graph) with N nodes, and edges numbered 1, 2, 3 ... N-1. Each edge have an integer value of assigned to it, representing its length.
We'll ask you to perfrom some instructions of the following form:
- DIST a b : Ask for the distance between Node a and node b
or
- kth a b k : Ask for The k -th node in the path from node a to node b
Example:
N = 6
1 2 1//Edge connects Node 1 and Node 2 have cost 1
2 4 1
2 5 2
1 3 1
3 6 2
Path from node 4 to node 6 is 4, 2, 1, 3, 6
DIST 4 6 : Answer is 5 (1 + 1 + 1 + 2 = 5)
KTH 4 6 4 : Answer is 3 (the 4-th node in the path from node 4 to node 6 is 3)
Input
The first line of input contains an integer T, the number of test cases (T <= 25). T test cases follow.
for each test case:
- in the first line there was an Integer n (n <= 10000)
- n -1 lines, the i-th line describes the i-th edge:a line with three integer S a b C denotes an edge between a , b of cost c ( Span style= "font-weight:700" >c <= 100000)
- the Next lines contain instructions < Span style= "font-weight:700" > "DIST a B" or "KTH a b k"
- the end of each test case was signified by the string "done ".
There is one blank line between successive tests.
Output
For each "DIST" or "KTH" operation, the write one integer representing its result.
Print one blank line after each test.
Example
Input:161 2 4 5 3 6 2DIST 4 6KTH 4 6 4DONEOutput:53
Title: DIST 4 6 Ask 4 to 6 distance, KTH 4 6 4, ask 4 to 6 for the 4th point
AC Code
#include <stdio.h> #include <string.h> #include <stdlib.h> #include <queue> #include <iostre Am> #define MAXN 10010using namespace std; int head[10010],cnt,vis[10010]; struct S {int u,v,w,next; }edge[10010<<1]; struct LCT {int bef[10010],pre[10010],next[10010][2],key[10010],sum[10010],belong[10010],num[10010]; void Init () {memset (pre,0,sizeof (pre)); memset (Next,0,sizeof (next)); } void Pushup (int x) {sum[x]=key[x]+sum[next[x][1]]+sum[next[x][0]]; num[x]=num[next[x][1]]+num[next[x][0]]+1; } void rotate (int x,int kind) {int y,z; Y=PRE[X]; Z=pre[y]; Next[y][!kind]=next[x][kind]; Pre[next[x][kind]]=y; Next[z][next[z][1]==y]=x; Pre[x]=z; Next[x][kind]=y; Pre[y]=x; Pushup (y); } void Splay (int x) {int rt; ForRT=X;PRE[RT];RT=PRE[RT]); if (X!=RT) {BEF[X]=BEF[RT]; bef[rt]=0; while (Pre[x]) {if (next[pre[x]][0]==x) {Rotat E (x,1); } else rotate (x,0); } pushup (x); }} void access (int x) {int fa; for (Fa=0;x;x=bef[x]) {splay (x); pre[next[x][1]]=0; Bef[next[x][1]]=x; NEXT[X][1]=FA; Pre[fa]=x; bef[fa]=0; Fa=x; Pushup (x); }} int query (int x,int y) {access (Y); for (Y=0;x;x=bef[x]) {splay (x); if (!bef[x]) return sum[y]+sum[next[x][1]]; pre[next[x][1]]=0; Bef[next[x][1]]=x; Next[x][1]=y; Pre[y]=x; bef[y]=0; Y=x; Pushup (x); }} int Select (int x,int k) {while (num[next[x][0]]+1!=k) {if (num[next[x][0]]+1>k) x=next[x][0];else{k-=num[next[x][ 0]]+1;X=NEXT[X][1];}} return x;} int KTH (int y,int x,int k) {access (Y); for (Y=0;x;x=bef[x]) {splay (x); if (!bef[x]) {if (num[next[x][1]]+1==k) return X;elseif (num[next[x][1]]+1>k) return Select (next[x][1],num[next[x][ 1]]-k+1); return select (Y,k-num[next[x][1]]-1);} pre[next[x][1]]=0; Bef[next[x][1]]=x; Next[x][1]=y; Pre[y]=x; bef[y]=0; Y=x; Pushup (x); }}}lct;void Add (int u,int v,int W) {edge[cnt].u=u; Edge[cnt].v=v; Edge[cnt].w=w; Edge[cnt].next=head[u]; head[u]=cnt++; } void BFs (int u) {int i,y; queue<int>q; memset (vis,0,sizeof (VIS)); Vis[u]=1; Q. push (U); while (!q.empty ()) {U=q.front (); Q.pop (); for (int i=head[u];i!=-1;i=edge[i].next) {int v=edge[i].v; if (!vis[v]) {lct.bef[v]=u; LCT.KEY[V]=LCT.SUM[V]=EDGE[I].W; Vis[v]=1; Q.push (v); }}}}int main () {int t;scanf ("%d", &t), while (t--) {int n,i;scanf ("%d", &n); Cnt=0;memset (Head,-1,sizeo F (head)), for (i=1;i<n;i++) {int u,v,w;scanf ("%d%d%d", &u,&v,&w); add (u,v,w); add (v,u,w);} Lct.init (); BFS (1); Char Op[10];while (scanf ("%s", op)!=eof) {if (!strcmp (OP, "done")) break;if (op[0]== ' D ') {int x, y; scanf ("%d%d", &x,&y);p rintf ("%d\n", Lct.query (x, y));} Else{int x,y,z;scanf ("%d%d%d", &x,&y,&z);p rintf ("%d\n", LCT. KTH (x, Y, z));}}}
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Spoj topic 913qtree2-query on a tree II (Link Cut tree query path K-point)