Successfully equipped with an/PEQ-1 laser range finder, Cao tested the m40a1 sniper rifle

The laserdesignator with the OFP original configuration is too big to carry, and it is very ugly to carry, and affects my carrying other equipment
(How do people carry a backpack on a radio station with such a big tripod? The battery also occupies three of my poll ).

(This issue is also reported in Iraq:
Many soldiers do not like the tripod of the gltd II system. They think it is too heavy to carry.
From --Marine Corps investigation report in Iraq
OFP is so real, coke-it is said that otaku would laugh so much)

So, I play the pirated and DIY spirit, Bas do an/PEQ-1 (soflam) stolen over, re-do config,
So we have a compact laser-directed Range Finder! It's very handsome to carry your back!

With a compact range finder, you must test the sniper rifle!
I took the LSR m40a1 with a range finder and drove the jeep to the desert island.
"Discover" the enemies of a class in a mountain. The Range Finder displays more than 800 meters.

This is the effect of the 800-meter distance to the eye! People are younger than ant financial ~~~~~!

How about 10 times the sight?

Since MOA was used in the past, I was not very familiar with the mildot on the m40a1 sight. I tried to correct one password and fire it,
It was found that the bullet crossed the head of the target.
No, it's close to the maximum range of M40 in 900 or more. Why isn't it so obvious?
In this case, the eight precision points on the sight won't be used at all.

Is it a sight multiple?
No. I used to play with SVD and m21.
Try again a few times, and finally there are several shots reaching 1 Password drops!
(What's wrong with this ?)
I looked at the bullet brand and told me about the game. Is this different from m118? Or is it the legendary Salt Lake City game?
Well, in this case, Masaka... (Jin Tian Yijia ke Nan's voice)
The problem can only be found in the following three places:

1. Is the bullet brand incorrect?
2. Is the sight multiples incorrect?
3. Is the rifle zero correct?

Well, well, Suo, Suo, it must be like this, it must be like this... (Talking to myself)

By the way, the infantry class.
I fixed a half-digit password, basically hitting their chest.
So when they found my position, they only rushed to the nearest 600 metres from me, and they were all put by me.
When a jeep was used for injury detection, almost all of them were killed.
It's a 7.62-caliber sniper rifle.

P.s.

After half an hour of meditation, I drew some sketch by the way, without precise calculation (I totally forgot
Calculation Method of the variation of the corresponding straight angle edge caused by the acute angle change of the right triangle), the following conclusions are to be confirmed:

Assume that the number of trajectory adjustments is 1 mil. If the sight is doubled (the object is not magnified by the mirror, what you see is what you get ),
The field of view adjustment should also be 1 mil (either the password point adjustment or the installation angle adjustment );
However, if the magnification of the sight changes, the field of view adjustment should change accordingly based on the variation rate.

For example, with a 10-fold sight, the image of an object inside the territory is magnified by 10 times (the angle of view is enlarged by 10 times ),
Therefore, the measurement of the sight density point at 1000 is reduced to one of the original 10 points.
In this field of view, the volume of 1 mil trajectory adjustment is reflected in the field of view adjustment of 10 mil (10 points of resolution.
-- However, it should be noted that the field of view adjustment only refers to the adjustment of the specified position in the sight.
The actual installation angle between the sight and the gun body is adjusted because the physical installation angle of the sight is not caused by the sight
The value varies according to the adjustment.

Yes?

Summary:

Installation Angle Adjustment Volume = trajectory adjustment volume

Or:

Resolution Point Adjustment = ballistic adjustment X scope Rate

P.s. 2:

A figure is shown in the pop-up area, revealing that the M24 sniper weapon system uses a sight with a fixed rate of 10 times of m3a Mil-dot sight.
.

Assuming that the figure is correctly flat at 10 times the rate, then I used the LSR m40a1 sight rate in OFP.
It is not 10 times. The following example describes how to use the three key points in the Y axis at a distance of 800:

Density adjustment = ballistic adjustment X scope Rate

It is concluded that 3 = The amount of ballistic adjustment X 10, then the amount of ballistic adjustment = 3/10

It is known that the number of ballistic adjustments of the m40a1 Of The LSR is 3/10, and the number of density adjustments is 1:

1 = 3/10 x sight rate, the sight rate is 10/3 = 3.33 times

That is to say, for an M24/M40 rifle with an accuracy of about 1 mil, shooting at a target of 800 meters,
If you use 3 times the sight, the resolution point adjustment is 1; if you use 10 times the sight, the resolution point adjustment is 3.

I'm a genius.

P.s. 3

The conclusion in p.s. 2 seems to have a small problem.
After careful study of the description of the m3a sight in the FM23-10 manual, it seems that this location is 10 times the standard distance.
(These 4 dots are spaced in 1 mil apart... A 1-meter target at a 1,000-meter range,
This target is the height between 2 dots, or the width between 2 dots .)

That is to say, a secret bit on m3a is equivalent to a 10-fold increase of 1mil (the distance of a secret bit on m3a is at a rate of 0.
),
Therefore, if you need to adjust 1mil (10 mil at a rate of 10), you only need to adjust one m3a password. Is it a little dizzy?