The "title" refers to numbers that contain only factors 2, 3, and 5 as ugly numbers (Ugly number).
* For example, 6, 8 are ugly numbers, but 14 is not because it contains factor 7. We used to think of 1 as the first ugly number. Find the nth ugly number in order from small to large.
Solution One: This solution commits a run timeout and is not recommended.
1 PackageCom.exe11.offer;2 3 /**4 * "title" refers to numbers that contain only factors 2, 3, and 5 (Ugly number). 5 * For example, 6, 8 are ugly numbers, but 14 is not because it contains factor 7. We used to think of 1 as the first ugly number. Find the nth ugly number in order from small to large. 6 * @authorWGS7 *8 */9 //This method will run out of time, M ... ..... ..... ....... ............ Ten Public classGetuglynumber { One Public BooleanIsuglynumber (intNumber ) { A while(number%2==0) -number/=2; - while(number%3==0) theNumber/=3; - while(number%5==0) -Number/=5; - return(number==1)?true:false; + - } + //returns the nth number of ugly A Public intGettheuglynumber (intN) { at if(n<=0) - return0; - intCount=0; - intUglynum=0; - while(uglynum<N) { -++count; in if(Isuglynumber (count)) { -uglynum++; to } + - } the returnCount//Nth number of ugly * $ }Panax Notoginseng Public Static voidMain (string[] args) { -Getuglynumber g=NewGetuglynumber (); the intNum=g.gettheuglynumber (1500); + System.out.println (num); A the } + - $ $ -}
Solution Two:
[Train of thought] a run time-out occurs. This method is to create an array first, since each ugly number is the result of the first few ugly number * *, so save it in the array first, and then in the array
Match If the same occurs, the current index+1 will be present.
PackageCom.exe11.offer;/*** "title" refers to numbers that contain only factors 2, 3, and 5 (Ugly number). * For example, 6, 8 are ugly numbers, but 14 is not because it contains factor 7. We used to think of 1 as the first ugly number. Find the nth ugly number in order from small to large. * [Train of thought] there is a run time-out. This method is to create an array first, since each ugly number is the result of the first few ugly numbers, so first save it in the array and then match in the array. If the same occurs, the current index+1 will be present. * @authorWGS **/ Public classGetuglynumber_solution2 { Public intGetuglynumber (intnum) { if(num<=0) return0; int[] uglynumbers=New int[num]; intNextuglynumberindex=1; uglynumbers[0]=1; intMultiplynumber2=0; intMultiplynumber3=0; intMultiplynumber5=0; while(nextuglynumberindex<num) { intMin=getmin (uglynumbers[multiplynumber2]*2, Uglynumbers[multiplynumber3]*, Uglynumbers[multiplynumber5]The); Uglynumbers[nextuglynumberindex]=min;//the smallest of the three ugly values in turn into the array 1th ... of 1500 valuesnextuglynumberindex++; if(uglynumbers[multiplynumber2]*2==min)//if the current value is just this ugly number, add amultiplynumber2++; if(uglynumbers[multiplynumber3]*3==min) MultiplyNumber3++; if(uglynumbers[multiplynumber5]*5==min) multiplyNumber5++; } intUglynum=uglynumbers[nextuglynumberindex-1]; returnUglynum; } Private intGetmin (intMultiplyNumber2,intMultiplyNumber3,intMultiplyNumber5) { intMin= (MULTIPLYNUMBER2<MULTIPLYNUMBER3)?Multiplynumber2:multiplynumber3; return(MIN<MULTIPLYNUMBER5)?Min:multiplynumber5; } Public Static voidMain (string[] args) {getuglynumber_solution2 g2=NewGetuglynumber_solution2 (); intN=g2.getuglynumber (1500); SYSTEM.OUT.PRINTLN (n); }}
The sword refers to the offer series---look for the ugly number