Usaco Section1.3 Combination Lock Problem Solving report

Combo Problem Solving Report--icedream61 Blog Park (reproduced please specify the source)
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Topic
A three-bit passcode lock, each of which may be valued 1~n. There are two unlocking codes that are given.
The lock can be unlocked if the attempted password is equal or similar to an unlocked password (up to 2 per bit value).
For example: (4,5,6) is a two unlock password, then (1,n,5) (2,4,8) can be unlocked, and (1,5,6) is not.
"Data Range"
1<=n<=100
"Input Sample"
50
1 2 3
5 6 7
"Output Example"
249
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Analysis
Direct enumeration.
It is important to note that two password-equal judgments are error prone (in cases where%n is required, the subscript does not start at 0, the difference is 2 and within the equivalent, and the difference 2 may occur simultaneously with%n).
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Summary
Once again AC.
Incidentally, with the syntax of the next overloaded operator and the built-in function of the class, there is a small question: if I put add and inrange two functions into the key class inside the code, then operator== cannot invoke the two functions. If anyone understands, hope to enlighten ~

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Code

1 /*2 id:icedrea13 Prob:combo4 lang:c++5 */6 7#include <iostream>8#include <fstream>9 using namespacestd;Ten  One intN; A  - intAddintXintY) {return(x+y-1+n)%n+1; } - BOOLInRange (intXintY) {returnx==y | | Add (x,1) ==y | | Add (x,2) ==y | | Add (x,-1) ==y | | Add (x,-2)==y;} the  - structKey - { -     intx, y, z +FriendBOOL operator= = (Key A,key b) {returnInRange (a.x,b.x) && inrange (A.Y,B.Y) &&InRange (A.Z,B.Z);} - }; +  A Key A, b; at  - intMain () - { -Ifstreaminch("combo.in"); -Ofstream out("Combo.out"); -  in     inch>>N; -     inch>>A.x>>A.y>>a.z; to     inch>>B.x>>B.y>>b.z; +  -     ints=0; the Key t; *      for(t.x=1; t.x<=n;++t.x) $          for(t.y=1; t.y<=n;++t.y)Panax Notoginseng              for(t.z=1; t.z<=n;++t.z) s+= (t==a| | t==B); -      out<<s<<Endl; the  +     inch. Close (); A      out. Close (); the     return 0; +}

Usaco Section1.3 Combination Lock Problem Solving report