UVA 10106-product (large number multiplication)

Source: Internet
Author: User

ProductTime limit:MS Memory Limit:0KB 64bit IO Format:%lld & %llu SubmitStatus



The problem

The problem is to multiply, integers X, Y. (0<=x,y<10250)

The Input

The input would consist of a set of pairs of lines. Each line in pair contains one multiplyer.

The Output

For each input pair of lines the output line should consist one integer the product.

Sample Input


Sample Output


Note that when the situation is 0, the situation is ignored at first. Don't forget to output 0 when either one is 0

#include <stdio.h> #include <string.h> #include <stdlib.h>char str1[1010],str2[1010];char a[1010],b    [1010],sum[1010];int Main () {int len1,len2;    int i,j;        while (~SCANF ("%s", str1)) {memset (a,0,sizeof (a));        Memset (b,0,sizeof (b));        memset (sum,0,sizeof (sum));        len1= strlen (STR1);        for (i=len1-1;i>=0;i--) a[len1-i-1]=str1[i]-' 0 ';        scanf ("%s", str2);        Len2=strlen (STR2);        for (i=len2-1;i>=0;i--) b[len2-i-1]=str2[i]-' 0 ';            for (i=0;i<len1;i++) {for (j=0;j<len2;j++) sum[i+j]+=a[i]*b[j];                    for (j=0;j<1010;j++) if (sum[j]>=10) {SUM[J+1]+=SUM[J]/10;                sum[j]%=10;        }} int flag=0; for (i=1010;i>=0;i--) {if (flag| |                Sum[i]) {flag=1;            printf ("%d", sum[i]); }} if(!flag) printf ("0");    printf ("\ n"); } return 0;}

UVA 10106-product (large number multiplication)

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