Test instructions: Given n points, M-Path, each road is represented by 5 integers u,v,a,b,t
U represents the beginning of the road, V is the end point, A is the open time, B is the closing time, T indicates the time required to pass the road
Look at the purple book, because the right side is no longer just the time on the road, but also need to deal with whether to wait
If you don't have to wait, the weight on this path is T.
If you need to wait, the weight of this road is t+wait.
You can use Dijkstra again.
1#include <iostream>2#include <cstdio>3#include <cstring>4#include <cmath>5#include <stack>6#include <vector>7#include <map>8#include <Set>9#include <queue>Ten#include <algorithm> One using namespacestd; A - #defineforeach (I,c) for (__typeof (C.begin ()) i = C.begin (); I! = C.end (); ++i) - thetypedefLong LongLL; - Const intINF = (1<< -)-1; - Const intMod=1000000007; - Const intmaxn=100005; + - intD[MAXN],USED[MAXN],NEXT[MAXN],FIRST[MAXN]; + intn,m,ecnt,s,t; A at structedge{ - intv,a,b,t; - } E[MAXN]; - - voidAddedge (intUintVintAintBintt) { -next[++ecnt]=First[u]; ine[ecnt].v=v; -E[ecnt].a=A; toe[ecnt].b=b; +e[ecnt].t=T; -first[u]=ecnt; the } * $ voidDijkstraints) {Panax Notoginseng for(intI=1; i<=n;i++) d[i]=INF; -d[s]=0; thememset (Used,0,sizeof(used)); + A for(intk=1; k<=n;k++){ the intu,m=INF; + for(intI=1; i<=n;i++)if(!used[i]&&d[i]<m) m=d[u=i]; -used[u]=1; $ for(inti=first[u];i!=-1; i=Next[i]) { $ intv=e[i].v,a=e[i].a,b=e[i].b,t=e[i].t; - - if(a<t)Continue;//The open time is less than the time passed the - intnow=d[u]% (A +b);Wuyi if(now+t<=a) {//now able to pass the case of the slack the if(d[v]>d[u]+t) d[v]=d[u]+T; - } Wu Else{ - intWait=a+b-now;//now need to wait for the case of the slack About if(d[v]>d[u]+wait+t) d[v]=d[u]+wait+T; $ } - } - } - A } + the intMain () { - intKase=0; $ while(SCANF ("%d %d%d%d", &n,&m,&s,&t)! =EOF) { thememset (first,-1,sizeof(first)); theEcnt=0; the the while(m--){ - intu,v,a,b,t; inCin>>u>>v>>a>>b>>T; the Addedge (u,v,a,b,t); the } About Dijkstra (s); the theprintf"Case %d:",++Kase); theprintf"%d\n", D[t]); + } - return 0; the}
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UVa 12661 Funny Car Racing "Dijkstra"