UVA-537 Artificial Intelligence?

http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=22452

This problem test instructions very simple, is in a line of string in a given voltage (U) current (I) power (P) 3 of any of the two let you ask for another, note that the string contains only two equals sign, and after 3 values may have a prefix, that is, there is kv,ma,mw and so on, K for 1000, M stands for 0.001 m for 1000000.

But do feel really worried, did not think of a good way to write out the code is long and messy, submitted always wrong, clearly on a number of situations, or can not think of where the wrong, but the reference to other people's code, it is very concise, or their own problems do less, no experience.

The key or only two equals in the string, then each time you find the equals sign, and then read into the following number, the corresponding conversion can be.

#include <iostream> #include <cstdio> #include <cmath> #include <vector> #include <cstring > #include <string> #include <algorithm> #include <string> #include <set> #include < functional> #include <numeric> #include <sstream> #include <stack> #include <map> #include <queue> #define CL (arr, Val) memset (arr, Val, sizeof (arr)) #define LL long long#define INF 0x7f7f7f7f#define LC l,m , Rt<<1#define RC m + 1,r,rt<<1|1#define pi ACOs ( -1.0) #define L (x) (x) << 1#define R (x) (x) <&lt ; 1 | 1#define MID (L, R) (L + R) >> 1#define Min (x, y) (x) < (y)? (x): (y) #define MAX (x, y) (x) < (y)? (y): (x) #define E (x) (1 << (x)) #define IABS (x) (x) < 0? -(x): (x) #define OUT (x) printf ("%i64d\n", x) #define LOWBIT (x) (x) & (-X) #define READ () freopen ("A.txt", "R", stdin) #define Write () freopen ("Dout.txt", "w", stdout), #define N 100005using namespace Std;int main () {  Read ();   int n,k,i,j;   char c;   Double a,w,p,u,i;   scanf ("%d", &n);   GetChar (); for (k=1;k<=n;k++) {p=0;       u=0;i=0;            for (j=0;j<2;j++) {while (scanf ("%c", &c)) if (c== ' = ') break;            scanf ("%lf%c", &a,&c);            U=s;            if (c== ' m ') {w=0.001;scanf ("%c", &c);}            if (c== ' K ') {w=1000;scanf ("%c", &c);}            if (c== ' M ') {w=1000000;scanf ("%c", &c);}            A*=w;            if (c== ' A ') i=a;            if (c== ' V ') u=a;            if (c== ' W ') p=a;       printf ("%.2lf\n", a);       } printf ("Problem #%d\n", k);       if (u&&i) printf ("p=%.2lfw\n", u*i);       if (u&&p) printf ("i=%.2lfa\n", p/u);       if (i&&p) printf ("u=%.2lfv\n", p/i);   printf ("\ n"); } return 0;}

UVA-537 Artificial Intelligence?